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Dennis_Churaev [7]
3 years ago
9

The radius of a circle is 4 centimeters. What is the circle's area?

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0

Answer:

50.24

Step-by-step explanation:

The area formula for a circle is pi times radius squared so 4 squared is 16 and then you multiply it by 3.14 and you get the answer 50.24

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The coordinates of the endpoints of AB and CD are A(2,
Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

m= \frac{y_2-y_1}{x_2-x_1}

Formula to Find Distance between two points

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

mAB ( represents , Slope of AB )

1. mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}

2. mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}

3. mCD=\frac{5-2}{6-5}=\frac{3}{1}=3

4. AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

5. BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

mAC = mBC  , and C is common point , hence these three are collinear points  making a straight line whole slope is -\frac{1}{3}

mAB=-\frac{1}{3}

mCD=3

mAB \times mCD = -\frac{1}{3} \times 3 = -1

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0
3 years ago
DUE TODAY! HELPPP
Yanka [14]

If 24 is a solutoin of x, n has to be 24 squared. 24*24=576

6 0
2 years ago
Read 2 more answers
How many positive integers $n$ with $n\le 500$ have square roots that can be expressed in the form $a\sqrt{b}$ where $a$ and $b$
My name is Ann [436]

Answer:

23

Step-by-step explanation:

6 0
3 years ago
Answer 6-9 for 12 points
gulaghasi [49]

Answer:

here ya go

Step-by-step explanation:

-5 + -4 = -9

17 - 6 = 11

(negatives cancel out) -13 + 5 = -8

(negs cancel out again) -6 + 3 = -3

7 0
3 years ago
The local library had a sale to get rid of the books that were slightly damaged it’s on paper back books for two dollars and har
kondor19780726 [428]

Answer:

The Local Library sold <u>31</u> hardcover books.

Step-by-step explanation:

Let number of paper back books be 'x'.

Let number of hardcover books be 'y'.

Given:

Total number of books sold = 89

Now Total number of books sold is equal to sum of number of paper back books and number of hardcover books.

framing in equation form we get;

x+y=89 \ \ \ \ \ equation \ 1

Now Given:

Cost of each paper back books = $2

Cost of each hardcover books = $5

Total Amount raised by library = $271

Now We know that Total Amount raised by library is equal to Cost of each paper back books multiplied by number of paper back books plus Cost of each hardcover books multiplied number of hardcover books.

framing in equation form we get;

2x+5y=271 \ \ \ \ equation \ 2

Now Multiplying equation 1 by 2 we get;

2(x+y)=89\times2\\\\2x+2y = 178 \ \ \ \ equation \ 3

Now Subtracting equation 3 from equation 2 we get;

(2x+5y)-(2x+2y)=271-178\\\\2x+5y-2x-2y=93\\\\3y = 93\\\\y=\frac{93}{3}=31

Substituting the value of y in equation 1 we get;

x+y =89\\\\x+31=89\\\\x =89-31 = 58

Hence The Local Library sold 58 paper back books and <u>31</u> hardcover books.

8 0
2 years ago
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