All categories

2 years ago

A baker needs more than 120 minutes to let their dough rise.

Mathematics

1 answer:

Sedaia [141]2 years ago

7 0

<u>Answer:</u>

m > 120

<u>Step-by-step explanation:</u>

<h3>How do we represent inequalities?</h3>

Inequalities are expressed using either the '>' or '<' symbols.

• The symbol '>' means "greater than". For example, 6 > 3, which means '6 is greater than 3'.

• The symbol '<' means "smaller than". For example, 5 < 9, which means '5 is smaller than 9.

In this example, if the baker needs more than 120 minutes, and <em>m</em> represents the number of minutes, then:

$\boxed{m > 120}$ .

This inequality means 'm is greater than 120'.

Learn more about inequalities here:

brainly.com/question/27983877

You might be interested in

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

3 years ago

Use the table to work out the values of a, b, c and d <br> PLEASE HELP!!!

Taya2010 [7]

Answer:

a = 10, b = 5, c = 14, d = 25

Step-by-step explanation:

Plug in -2 for x ....

y = 2(-2)^2 + -2 + 4

y = 2(4) + 2

y = 10

Plug in -1 for x ....

y = 2(-1)^2 + -1 + 4

y = 2(1) + 3

y = 5

Plug in 2 for x ....

y = 2(2)^2 + 2 + 4

y = 2(4) + 6

y = 8 + 6

y = 14

Plug in 3 for x ....

y = 2(3)^2 + 3 + 4

y = 2(9) + 7

y = 18 + 7

y = 25

8 0

2 years ago

A student solved this problem and said the answer is 1 3/4 quarts. Gary mixed 1/4 quart of plain milk and 2/3 quart of chocolate

levacccp [35]

Gary is wrong. the answer is 11/12.

1/4 + 2/3= n
1/4= 3/12
2/3= 8/12
3/12+8/12= 11/12 .
So, the answer cannot be 1 & 3/4.

6 0

3 years ago

Factorize 5xz - 10xy

mr_godi [17]

Step-by-step explanation:

5xz-10xy
5x(z-2y)

hope it helps.

<h2>stay safe healthy and happy.....</h2>

5 0

3 years ago

The arc shown is 140 degrees. Find the measure of angle 1.

Elodia [21]

The angle subtended by two chords is half the enclosed arc measure. If we imagine one of the chords getting shorter and shorter this remains true. In the limit the shrinking chord becomes a tangent, and the angle is still half the arc measure.

Answer: 70 degrees

3 0

3 years ago