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Schach [20]
2 years ago
5

Simplify ASAP!!!! -15x*3+40-(-4x*5)

Mathematics
2 answers:
Drupady [299]2 years ago
8 0
- - Let's solve:
Starting off by solving:

We have

-15x*3+40--4x*5


Which can be made into:


-45x+40+20x


Now we have to combine like terms to complete our answer.

-45x+40+20x

-45x+20x+40

-25x+40 is your final answer.


ValentinkaMS [17]2 years ago
6 0
<span>⚓️Let's simplify this Step-By-Step!
</span>⚓️<span>Question:
</span><span><span><span>(<span>−15x</span>)</span>(3)</span>+40</span>−<span><span>(<span>−4x</span>)</span><span>(5<span>)
</span></span></span><span><span>−45x</span>+40</span>+<span>20<span>x
</span></span>
<span>⚓️Now Combine Like Terms:
</span><span><span>−45x</span>+40</span>+<span>20x
</span><span>(<span><span>−45x</span>+20x</span>)</span>+<span>(40<span>)
</span></span>
⚓️Your answer is:
<span>−25x</span>+40

⚓️I hope this helps!⚓️
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Step-by-step explanation:

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4 0
2 years ago
Given right triangle ABCABC with altitude \overline{BD} BD drawn to hypotenuse ACAC. If BC=10BC=10 and DC=5,DC=5, what is the le
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Answer: \overline{AC}= 12.5

Step-by-step explanation: The triangle ABC and its altitude \overline{BD} is represented in the figure below.

<u>Altitude</u> is a segment of line that link a vertex and the opposite side, forming a right angle.

So, because of \overline{BD}, now we have two similar triangles, which means that ratios of corresponding sides are equal:

\frac{\overline{BD}}{\overline{BC}} =\frac{\overline{AD}}{\overline{BD}}

\overline{BD}^{2}=\overline{BC}.\overline{AD} (1)

This is always true for a right triangle and a altitude drawn to the hypotenuse.

Triangle BDC is also right triangle. So, we can use Pythagorean theorem to determine the missing side.

\overline{BC}^{2}=\overline{CD}^{2}+\overline{BD}^{2}

\overline{BD}^{2}=\overline{BC}^{2}-\overline{CD}^{2} (2)

Substituting (2) into (1):

\overline{BC}^{2}-\overline{CD}^{2}=\overline{BC}.\overline{AD}

We want to find f, so:

\overline{AD}=\frac{\overline{BC}^{2}-\overline{CD}^{2}}{\overline{BC}}

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The length of \overline{AC} is

\overline{AC}=f+5

\overline{AC}=7.5+5

\overline{AC}=12.5

The length of the hypotenuse of triangle ABC is 12.5 units.

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