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3 years ago

What is 965 divided by 5

Mathematics

2 answers:

Afina-wow [57]3 years ago

8 0

The answer would be 193

Slav-nsk [51]3 years ago

5 0

193 would be the answer

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Are the given lenghts a right triangle? 28, 53,45

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Yes that should be correct

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3 years ago

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What is the simplified value of the exponential expression 64 1/3?

notka56 [123]

Hi there!

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I believe your answer is:

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Here’s why:

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I am assuming that the fraction is supposed to be the exponent.

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$64^{\frac{1}{3}}\\--------\\\rightarrow \text{Recall the exponent rule: } a^{\frac{m}{n}}=(\sqrt[n]{a})^m\\\\\\\rightarrow \sqrt[3]{64}\\\\\rightarrow \boxed{4}$

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Hope this helps you. I apologize if it’s incorrect.

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3 years ago

A gas station charges $2.19 per gallon of gas. Use function notaion to describe the relationship between the total cost C(g) and

mr Goodwill [35]

For every gallon i would spend 2.19$

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3 years ago

Find the nth term of -5,-2,3,10,19

mixer [17]

Answer:

PLace them one by one from big number to small and the middle number is the answer.

Step-by-step explanation:

7 0

3 years ago

Find the values of λ for which the determinant is zero.

elena55 [62]

Answer:

Determinant are special number that can only be defined for square matrices.

Step-by-step explanation:

Determinant are particularly important for analysis. The inverse of a matrix exist, if the determinant is not equal to zero.

How to find determinant

For a 2×2 matrix

$det ( \left[\begin{array}{cc}x&y\\a&z\end{array}\right] ) = xz-ay$

For a 3×3 matrix

we first decompose it to 2×2

$det (\left[\begin{array}{ccc}k&l&m\\o&p&q\\r&s&t\end{array}\right] )\\\\= k*det(\left[\begin{array}{cc}p&q\\s&t\end{array}\right] ) - l*det(\left[\begin{array}{cc}o&q\\r&t\end{array}\right] ) + m*det(\left[\begin{array}{cc}o&p\\r&s\end{array}\right] ) \\\\=k(pt-sq) - l(ot-rq) + m(os-rp)$

Example

Find the values of λ for which the determinant is zero

$\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right]$

$det(\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right])\\\\= s*det(\left[\begin{array}{cc}s&-1\\-1&1\end{array}\right] ) - (-1)*det(\left[\begin{array}{cc}-1&-1\\0&1\end{array}\right] ) + 0*det(\left[\begin{array}{cc}-1&s\\0&-1\end{array}\right] )\\\\= s(s(1)-(-1*-1)) - (-1)(-1*1 - (-1*0)) + 0\\= s(s - 1)) + 1(-1 + 0) \\=s^{2} -s-1$

Equating the determinant to zero

$s^{2} -s-1 =0\\$

s = $\frac{1}{2}$ * (1 ±5 )

s = 1.61 or -0.61

5 0

3 years ago