Answer:
60 and 25
Step-by-step explanation:
The range is the difference between the maximum value and the minimum value.
maximum value = 125, minimum value = 65
range = 125 - 65 = 60
------------------------------------------
The interquartile range is the difference between the upper quartile Q₃ and the lower quartile Q₁
Q₃ is the value at the right side of the box = 115
Q₁ is the value at the left side of the box = 90
interquartile range = 115 - 90 = 25
I really hope this helps you!
Answer:
Around 8.8
Step-by-step explanation:
This problem requires the Pythagorean Theorem. We are given the hypotenuse and a leg, so we can plug in what we know.
A fleet of nine taxis is to be dispatched to three airports in such a way that three go to airport A, five go to airport B, and one goes to airport C. In how many distinct ways can this be accomplished?
2.44) Refer to Exercise 2.43. Assume that taxis are allocated to airports at random.
a) If exactly one of the taxis is in need of repair, what is the probability that it is dispatched to airport C?
b) If exactly three of the taxis are in need of repair, what is the probability that every airport receives one of the taxis requiring repairs?
So, my answer to 2.44a is 1/9. Hopefully this is correct at least :)
For 2.44b, my guess was
(3C1)(1/3)(2/3)2 * (5C1)(1/3)(2/3)4 * 1/3
The solutions manual on chegg (which seems to be riddled with errors) says something completely different. Is my calculation correct?
