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hoa [83]
3 years ago
9

What are the cons of graphing, elimination, and substitution?

Mathematics
1 answer:
rosijanka [135]3 years ago
4 0

GRAPHING CONS

1) hard to graph by hand. Often you need a graphics calculator or a computer software like maple or matlab. Or the graph has to be given.

2) hard to tell the exact solution, just by observing point of intersection. for example if x = 2.8675, the viewer would say x= 3.

3) sometimes not easy to decide the axis window of y and x axis. For example if the solution is very large like x = 100000 and your graph ends at x = 100, you cannot see the solution

SUBSTITUTION CONS

1) Becomes tedious if a system has too many equations or variables

ELIMINATION PROS/CONS

1) basically same as substitution

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Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 5.00. What should be the length of B⃗ so that th
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Answer:

Length of B is 7.4833

Step-by-step explanation:

The vector sum of A and B vectors in 2D is

C=A+B=(a_1+b_1,a_2+b_2)

And its magnitude is:

C=\sqrt{(a_1+b_1)^2+(a_2+b_2)^2} =9

Where

a_1=Asinx

a_2=Acosx

b_1=Bsin(x+90)

b_2=Bcos(x+90)

Using the properties of the sum of two angles in the sin and cosine:

b_1=Bsin(x+90)=B(sinx*cos90+sin90*cosx)=Bcosx

b_2=Bcos(x+90)=B(cosx*cos90-sinx*sin90)=-Bsinx

Sustituying in the magnitud of the sum

C=\sqrt{(Asinx+Bcosx)^2+(Acosx-Bsinx)^2} =9

C=\sqrt{A^2sin^2x+2ABsinxcosx+B^2cos^2x+A^2cos^2x-2ABsinxcosx+B^2sin^2x} =9

C=\sqrt{A^2(sin^2x+cos^2x)+B^2(cos^2x+sin^2x)}

C=\sqrt{A^2+B^2} =9

Solving for B

A^2+B^2 =9^2

B^2 =9^2-A^2

Sustituying the value of the magnitud of A

B^2=81-5^2=81-25=56

B= 7. 4833

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