Let
x---------> first positive integer
x+1------> second positive integer
x+2-----> third positive integer
we know that
(x+1)*(x+2)=72-------> x² +2x+x+2=72 -------> x² +3x-70=0
using a graph tool-------> <span>I solve the quadratic equation
</span>see the attached figure
the roots are
x1=-10
x2=7
the answer is
first positive integer is x=7
second positive integer is x+1=8
third positive integer is x+2=9
The Tenths place because it's the first
Answer:
t =log(20) / 0.3 = 10*log(20) / log(1,000) - years - when the tree will have 100 branches.
Step-by-step explanation:
100 = 5 * 10^(0.3t), solve for t
Divide both sides by 5:
20 =10^(0.3t)
Take the log of both sides:
0.3t =log(20)
Divide both sides by 0.3:
Multiply the RHS by 10 / 10
t =log(20) / 0.3 = 10*log(20) / log(1,000) - years - when the tree will have 100 branches.
Answer:
1 describe the inequality graph