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3 years ago

What is the area of rectangle ABCD?

Mathematics

2 answers:

Ghella [55]3 years ago

7 0

Answer:

Step-by-step explanation:

Area of a Rectangle: A = lw

Since our <em>l</em> is 3 and our <em>w</em> is 4, we plug them in:

A = 3(4)

A = 12

Alternatively, we count the squares in the rectangle to get 12 as our answer.

larisa86 [58]3 years ago

5 0

Answer:

Area = 12 square units

Step-by-step explanation:

Area of Rectangle = Length*Width

Where Length = 3 units, Width = 4 units

Area = 3*4

Area = 12 square units

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A recent poll of 120 randomly selected adults who frequent the local farmer's market found that 54 have purchased reusable clot

Olenka [21]

Answer:

95% Confidence interval: (0.361,0.539)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 120

Number of farmers who reusable cloth bags, x = 54

$\hat{p} = \dfrac{x}{n} = \dfrac{54}{120} = 0.45$

95% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96$

Putting the values, we get:

$0.45\pm 1.96(\sqrt{\dfrac{0.45(1-0.45)}{120}}) = 0.45\pm 0.089\\\\=(0.361,0.539)$

is the required 95% confidence interval for the proportion of adults who have purchased reusable cloth bags.

3 0

3 years ago

Allison bought jelly beans to share with her friends. She bought pounds of blueberry jelly beans and pounds of lemon jelly beans

Vaselesa [24]

Answer: $1\dfrac{11}{12}\text{ pounds}$

Step-by-step explanation:

The complete question is provided in the attachment.

Given, Amount blueberry jelly beans= $1\dfrac{1}{4}$ pounds

$=\dfrac{5}{4}$ pounds.

Amount lemon jelly beans = $2\dfrac{1}{3}$ pounds

$=\dfrac{7}{2}$ pounds

Total jelly beans she bought = Amount blueberry jelly beans + Amount lemon jelly beans

$=(\dfrac{5}{4}+\dfrac{7}{3})$ pounds

$=\frac{15+28}{12}\text{ pounds}\\\\=\dfrac{43}{12}\text{ pounds}$

Amount of jelly beans she gave away = $1\dfrac{2}{3}=\dfrac{5}{3}\text{ pounds}$

Amount of jelly beans she has left= Total jelly beans - Amount of jelly beans she gave away

= $\dfrac{43}{12}-\dfrac{5}{3}\\\\=\dfrac{43-20}{12}\\\\=\dfrac{23}{12}\\\\=1\dfrac{11}{12}\text{ pounds}$

She has left $1\dfrac{11}{12}\text{ pounds}$ of jelly beans.

6 0

3 years ago

The teacher passed out math books.The length is 10 inches and the width is 8 inches.What is the perimeter of each book?

miv72 [106K]

Answer: The perimeter of each book is: " 36 in. " .

__________________________________________________

Step-by-step explanation:

__________________________________________________

Note that the given units are all in "inches (in.)" .

Use the formula for the "perimeter of a rectangle" ;

{which happens to work for a "square" as well;

since a "square" is a rectangle.}.

__________________________________________________

This is based on the assumption that the book is shaped like a

"rectangle" (or "square" —which is a rectangle).

__________________________________________________

The formula for the Perimeter of a rectangle is:

P = 2 L + 2 w ;

in which:

P = the perimeter of the rectangle;

for which we shall solve; [in "inches (in.)" ] ;

L = the length of the rectangle = 10 in. (given) ;

w = the width of the rectangle = 8 in. (given) .

___________________________________________________

Now, plug the given values for the "length (L)" and the "width (w)" ;

as follows:

___________________________________________________

P = (2 * 10 in.) + (2 * 8 in.) ;

P = (20 in.) + (16 in.) ;

P = 36 in.

___________________________________________________

Answer: The perimeter of each book is: " 36 in. " .

___________________________________________________

Hope this helps!

Best wishes in your academic pursuits

— and within the "Brainly" community!

___________________________________________________

3 0

3 years ago

The area of a triangle is the product of the base of the triangle times the height of the triangle, divided by two.

Natali [406]

Answer:

A = (1/2)(base)(height)

Step-by-step explanation:

Yes, that's correct:

A = (1/2)(base)(height)

Was there more to this question?

3 0

3 years ago

In order to determine if there is a significant difference between campuses and pass rate, the chi-square test for association a

RUDIKE [14]

Answer:

57.5

Step-by-step explanation:

The expected frequency of West Campus and Failed :

Let :

Failed = F

East Campus = C

West Campus = W

Passed = P

Frequency of FnW :

[(FnE) + (FnW) * (PnW) + (FnW)] / total samples

[(52 + 63) * (63 + 37)] / 200

[(115 * 100)] / 200

11500 / 200

= 57.5

n(Failed n East campus)

5 0

2 years ago