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3 years ago

Given EG = 16 and FH = 12, what is the length of one side

Mathematics

2 answers:

pav-90 [236]3 years ago

6 0

8 is the answer cuz if you dive and all that

DIA [1.3K]3 years ago

3 0

Answer: 10 units

Step-by-step explanation:

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Create a memory device to help you remember the quadratic formula. The device could be a song, drawing, rhyme, mnemonic device,

Lostsunrise [7]

Answer:

q-u-a-d-r-a-t-i-c f-o-r-m-u-l-a

Step-by-step explanation:

6 0

3 years ago

Here is a histogram displaying the top 30 lifetime batting averages in baseball history. This distribution of data shows lots of

Evgesh-ka [11]

The correct answer to this question is letter "<span> C. There may be other hitters in the 320s, but they didn't make the top 30." </span>his distribution of data shows lots of lifetime averages in the middle classes, but tails off sharply at both the upper and lower ends. The statement that best explains the fact that there are very few averages in the lowest class is that t<span>here may be other hitters in the 320s, but they didn't make the top 30.</span>

8 0

3 years ago

Read 2 more answers

Attachment Mathswatchhhh!!!!!!!!!

Alexus [3.1K]

Answer:

(a) draw the graph using these coordinates :

(0,-1) and (3,1)

(b) x = 3

6 0

3 years ago

Say that the economy is in an expansion, causing wages to increase by six percent. if you previously received a monthly salary o

Westkost [7]

From previously received a monthly salary of $1,375.00, Your new monthly salary increase by six percent would be $1,457.50.

What is the percentage?

A percentage is a minimum number or ratio that is measured by a fraction of 100.

You previously received a monthly salary of $1,375.00

Now by economic expansion, causing wages to increase by 6%

Increment of the salary = 6% of 1,375.00

= 6/100 × 1,375

= 0.06 × 1,375

= $82.50

So, your new monthly salary would be = $1,375.00 + $82.50

= $1,457.50

Hence, your new monthly salary would be $1,457.50.

Learn more about percentages;

brainly.com/question/13450942

8 0

2 years ago

Find the nth degree polynomial function with real coefficients satisfying the given conditions.

RUDIKE [14]

$\bf (x+1)(x-3)(x-2-4i)(x-2+4i)
\\\\
\textit{now, let's take a peek at }(x-2-4i)(x-2+4i)\\
\textit{and recall our }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
(x-2-4i)(x-2+4i)\implies [(x-2)-(4i)][(x-2)+(4i)]
\\\\\
[(x-2)^2-(4i)^2]\implies [(x^2-2x+4)-(4^2\boxed{i^2})]
\\\\\
[(x^2-2x+4)-(16\cdot \boxed{-1})]\implies [(x^2-2x+4)+16]
\\\\
(x^2-2x+20)\\\\
-----------------------------$

$\bf thus
\\\\

\begin{array}{llll}
(x+1)(x-3)\\(x-2-4i)(x-2+4i)
\end{array}\implies (x+1)(x-3)(x^2-2x+20)
\\\\\\
(x^2-2x-3)(x^2-2x+20)\implies 
\begin{array}{llll}
x^4-2x^3+20x^2-2x^3\\+4x^2-40x+3x^2-6x+60
\end{array}
\\\\\\
x^4-4x^3+27x^2-46x+60$

4 0

3 years ago