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Novosadov [1.4K]
2 years ago
9

Solve the quadratic equation numerically (using tables of x- and y- values). x squared + 5 x + 6 = 0 a. x = -3 or x = -2 c. x =

-3 or x = -3
Mathematics
2 answers:
sineoko [7]2 years ago
6 0

Answer:

22

Step-by-step explanation:

I did it on math class

sladkih [1.3K]2 years ago
3 0

Answer:

2 solutions:  -2 and -3

Step-by-step explanation:

x² + 5x + 6 has the following factors:  (x+3)(x+2) = 0

x+3 = 0; one solution is -3

x+2 = 0; second solution is -2

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Grapes cost $1.55 per pound. What equation is used to find c the total cost of p pounds of grapes?
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C=$1.55p

Is this what you need?
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Walter buys a bus pass for $30 every time he rides the bus money is deducted from the value of the pass he rode 12 times and $24
klemol [59]
So each time, 24/12 or $2 was deducted per trip

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3 years ago
What would be the total area of a piece of land that was made up of three squares that each has a side length of 4x-2?
Darya [45]

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48x^2-48x+12

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4 0
3 years ago
Determine the current through each of the LEDs in the circuits below. Which LED will be
Anika [276]

a. I = 6. 1 × 10^-4 A

b. I = 2. 6 × 10^-3 A

c. I = 0. 04 A

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

<h3>How to determine the current</h3>

The formula for finding current

I = V/R

Where v = voltage

R = resistance

A. V = 12V

R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

I = \frac{12}{19700}

I = 6. 1 × 10^-4 A

B. V = 9V

R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

I = \frac{12}{4700}

I = 2. 6 × 10^-3 A

C.  V=  12V

1/R = \frac{1}{750} + \frac{1}{1200} + \frac{1}{950 } = 3. 22 × 10^-3

R = \frac{1}{3. 22 * 10 ^-3} = 310. 56 Ω

I = \frac{12}{310. 56}

I = 0. 04 A

It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

Learn more about Ohms law here:

brainly.com/question/14296509

#SPJ1

8 0
1 year ago
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