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Basile [38]
3 years ago
7

Using fraction bar to find sum for 1/3 1/3 1/6

Mathematics
2 answers:
PIT_PIT [208]3 years ago
8 0
1/3 1/3 1/6= 1+1=2/6 1/6=3/6 simply it to 1/2
Slav-nsk [51]3 years ago
8 0

Answer:

5y7777777777ewnaujhswfqasDAFfawtgshjyllu;9l8uky7jthrfh

Step-by-step explanation:

:)))))))))))))

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Please help me! I will mark you brainliest!
Masja [62]

Answer:

Second option is the correct choice.

Step-by-step explanation:

k=6\quad and \quad E(X)=\frac{-7\:\:}{15}

Regards: Umer

5 0
3 years ago
What's the answer to this problem?
Olenka [21]
<span>144.222051019 :DDDDDDD remember to round</span>
4 0
3 years ago
An equation for the depreciation of a car is given by y = A(1 – r)t , where y = current value of the car, A = original cost, r =
avanturin [10]

Answer:

D

Step-by-step explanation:

We know that the equation for the depreciation of the car is:

y=A(1-r)^t

Where y is the current cost, A is the original cost, r is the rate of depreciation, and t is the time, in years.

We are told that the value of the car now is half of what it originally cost. So:

y=\frac{1}{2}A

Substitute this for y:

\frac{1}{2}A=A(1-r)^t

We also know that the rate of depreciation is 10% or 0.1. Substitute 0.1 for r:

\frac{1}{2}A=A(1-0.1)^t

So, let's solve for t. Divide both sides by A:

\frac{1}{2}=(1-0.1)^t

Subtract within the parentheses:

\frac{1}{2}=(0.9)^t

Take the natural log of both sides:

\ln(\frac{1}{2})=\ln((0.9)^t})

Using the properties of logarithms, we can move the t to the front:

\ln(\frac{1}{2})=t\ln(0.9)

Divide both sides by ln(0.9):

t=\frac{\ln(\frac{1}{2})}{\ln(0.9)}

Use a calculator. So, the car is approximately:

t\approx6.6\text{ years old}

Our answer is D.

And we're done!

7 0
3 years ago
Can someone show me how to do this?<br><br> 16! / 4! 12!
olga nikolaevna [1]
What do you mean lol, there is no such thing as that in math. if your question is 16/412 then let me know

3 0
3 years ago
A farm increases in value from $800,000 to $1,100,000 over a period of 6 years. Use the formula r=(F/P)^1/n−1 to find the annual
enot [183]

Answer:

Step-by-step explanation:

The formula representing the the annual inflation rate r is expressed as

r = (F/P)1/n−1

Where

n represents the the number of years during which the value increases from P to F

A farm increases in value from $800,000 to $1,100,000 over a period of 6 years. This means that

P = $800,000

F = $1,100,000

n = 6

Therefore,

r = (1100000/800000)1/6−1

r = 1.375/5 = 0.275

6 0
3 years ago
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