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Flauer [41]
3 years ago
9

At the beginning of a 10-hour experiment,a substance has an initial temperature of 19.7 degrees C. The substance is cooled at a

constant rate of 2.6 degrees C per hour. What is the temperature of the substance at the end of the experiment?
Justify your answer using words and math. Explain.
Mathematics
1 answer:
Olin [163]3 years ago
3 0

Answer:

-6.3

Step-by-step explanation:

2.6 * 10 (10 hours and 2.6 degrees) = 26

19.7 - 26 = -6.3



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Which value of c makes the ratios equal? *
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Answer:

Option 4

The answer is 10.8

Step-by-step explanation:

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Thus, The value of c is 10.8

<h3><u>For </u><u>Verification</u>;</h3>

5/6 = 9/c

5/6 = 9/10.8

0.833 = 0.833

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3 0
2 years ago
I need help with like terms
professor190 [17]
I’m guessing you mean like this.
2x+4y+5x+8y.
2x and 5x are like terms because the x’s are alike. If you add 2+5, the answer is 7. So therefore 2x+5x=7x.

4y and 8y are like terms because the y’s are alike. So the answer to 4y+8y would be 12y.

If you need extra help, give me a problem and I will help you solve it.
7 0
3 years ago
Find the exact value of tan(165°) using a difference of two angles
Katyanochek1 [597]

Answer:  -2+\sqrt{3}

=========================================================

Work Shown:

Apply the following trig identity

\tan(A - B) = \frac{\tan(A)-\tan(B)}{1+\tan(A)*\tan(B)}\\\\\tan(225 - 60) = \frac{\tan(225)-\tan(60)}{1+\tan(225)*\tan(60)}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+1*\sqrt{3}}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\

Now let's rationalize the denominator

\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\\tan(165) = \frac{(1-\sqrt{3})(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\\tan(165) = \frac{(1-\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{(1)^2-2*1*\sqrt{3}+(\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{1-2\sqrt{3}+3}{1-3}\\\\\tan(165) = \frac{4-2\sqrt{3}}{-2}\\\\\tan(165) = -2+\sqrt{3}\\\\

----------------------

As confirmation, you can use the idea that if x = y, then x-y = 0. We'll have x = tan(165) and y = -2+sqrt(3). When computing x-y, your calculator should get fairly close to 0, if not get 0 itself.

Or you can note how

\tan(165) \approx -0.267949\\\\-2+\sqrt{3} \approx -0.267949

which helps us see that they are the same thing.

Further confirmation comes from WolframAlpha (see attached image). They decided to write the answer as \sqrt{3}-2 but it's the same as above.

5 0
3 years ago
Solve the inequality -2(k+3) &lt; -2k - 7
ExtremeBDS [4]
This equation would be represented as a No Solution equation. Due to the fact that if you do inverse operation and combine like terms, your variables will cancel out.
8 0
4 years ago
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