Step-by-step explanation:
the answer is in the above image
Answer: 21
Step-by-step explanation:
Given: Number of mango guava and sapota are supplied 108,84 and 60 respectively.
Since, 108 = 2 x 2 x 3 x 3 x 3
84 = 2 x 2 x 3 x 7
60 = 2 x 2 x 3 x 5
HCF(108,84,60) = 2 x 2 x 3 [HCF=Highest common factors]
= 12
Greatest number of plants in each row = 12
Number of rows for mango = 
Number of rows for guava = 
Number of rows for sapota = 
Total rows = 9+7+5= 21
Hence, the minimum number of rows in which they can be planted if in each row same numbers of saplings of the same type are to be planted = 21
Answer:
around 13.18
Step-by-step explanation:
the middle square is 2*2 = 4
the triangle then is 2^2 + 6^2 = 40 -> sqrt40 = 6.325
and then 2^2 + 2^2 = 8 -> sqrt8 = 2.828
4+6.325+2.828 = 13.18
Y = x^2 - 8x + 5 Put brackets around the first two terms.
y = (x^2 - 8x ) + 5 Add (8/2)^2 on the inside of the brackets. Translated into mathese that means take 1/2 of the linear term (8x), drop the x and square the rest
.
(1/2 8)^2 = 4^2 = 16
y = (x^2 - 8x + 16) - 5 What you put inside the brackets, you must subtract outside the brackets.
y = (x^2 - 8x + 16) - 5 - 16 Combine like terms.
y = (x^2 - 8x + 16) - 21 Show what is inside the brackets as a square.
y = (x - 4)^2 - 21 <<<<<<<<< Answer.