Can someone help me? Q: Here is the sales slip from Sharon's shopping trip. Sharon paid a total of $25.52 which included sales t
1 answer:
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Find the powers
$a^{2}=5+2 \sqrt{6}$
$a^{3}=11 \sqrt{2}+9 \sqrt{3}$
The cubic term gives us a clue, we can use a linear combination to eliminate the root 3 term $a^{3}-9 a=2 \sqrt{2}$ Square $\left(a^{3}-9 a\right)^{2}=8$ which gives one solution. Expand we have $a^{6}-18 a^{4}-81 a^{2}=8$ Hence the polynomial $x^{6}-18 x^{4}-81 x^{2}-8$ will have a as a solution.
Note this is not the simplest solution as $x^{6}-18 x^{4}-81 x^{2}-8=\left(x^{2}-8\right)\left(x^{4}-10 x^{2}+1\right)$
so fits with the other answers.
9514 1404 393
Answer:
see the attachment for a graph
Step-by-step explanation:
With the given point and slope, the equation of the line can be written in point-slope form:
y -k = m(x -h) . . . . . line with slope m through point (h, k)
y -2 = 1/2(x +1) . . . . line with slope 1/2 through point (-1, 2)
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Slope is the ratio of rise to run, so a slope of 1/2 means the line will rise 1 unit for each 2 units of run (to the right). If you're plotting this by hand, you can identify a second point that is 2 right and 1 up from the given point:
(-1 +2, 2 +1) = (1, 3).
You can draw your line through those two points.
