Answer:
It looks like the third one, C
Step-by-step explanation:
Every time c increases by 1, d increases by 2
That means the slope will be 1/2
That means the slope is positive
Which means that there can only be one answer, C
Answer:
8πcm²/sec
Step-by-step explanation:
The radius of the circle increases at a rate of dr/dt = 0.25cm/sec
The radius of the circle r = 16cm
The area of the circle increases at a rate of dA/dt = ?
Area of a circle = πr²
We take the derivative with respect to t
dA/dt = 2πrdr/dt
dA/dt = 2 π (16)(0.25)
dA/dt = 8πcm²/sec
Thank you!!!
Answer:
The measure of angle < AED is 
Step-by-step explanation:
we know that
The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite.
so

substitute the values and solve for x






-----> by supplementary angles
substitute value


You are trying to find an x-value for which f(x) = g(x). At first your choice of x is arbitrary. In the given table, the first x-value tried was 0 (zero). For this value of x, f(x) does NOT equal g(x).
Next x was 1. f(x) and g(x) are even further apart here. So reject 1 and try 2 instead. Notice how f(x) and g(x) are closer together now than they were for x=1.
Note that for x=2.5, f(x) and g(x) are even closer together; ony 0.75 separates them.
Your turn. Try x=2.4, x=2.3, and so on. You may have to go in the other direction: Try x=2.6, x=2.7, and so on. If f(x) and g(x) are getting closer to one another, you're going in the right direction; if further apart, you're going in the wrong direction.
Have fun. This really is an interesting problem.
If you're using the app, try seeing this answer through your browser: brainly.com/question/2264253_______________
Evaluate the indefinite integral:

Trigonometric substitution:

then,
![\begin{array}{lcl} \mathsf{x=sin\,\theta}&\quad\Rightarrow\quad&\mathsf{dx=cos\,\theta\,d\theta\qquad\checkmark}\\\\\\ &&\mathsf{x^2=sin^2\,\theta}\\\\ &&\mathsf{x^2=1-cos^2\,\theta}\\\\ &&\mathsf{cos^2\,\theta=1-x^2}\\\\ &&\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\checkmark}\\\\\\ &&\textsf{because }\mathsf{cos\,\theta}\textsf{ is positive for }\mathsf{\theta\in \left[\dfrac{\pi}{2},\,\dfrac{\pi}{2}\right].} \end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Blcl%7D%20%5Cmathsf%7Bx%3Dsin%5C%2C%5Ctheta%7D%26%5Cquad%5CRightarrow%5Cquad%26%5Cmathsf%7Bdx%3Dcos%5C%2C%5Ctheta%5C%2Cd%5Ctheta%5Cqquad%5Ccheckmark%7D%5C%5C%5C%5C%5C%5C%20%26%26%5Cmathsf%7Bx%5E2%3Dsin%5E2%5C%2C%5Ctheta%7D%5C%5C%5C%5C%20%26%26%5Cmathsf%7Bx%5E2%3D1-cos%5E2%5C%2C%5Ctheta%7D%5C%5C%5C%5C%20%26%26%5Cmathsf%7Bcos%5E2%5C%2C%5Ctheta%3D1-x%5E2%7D%5C%5C%5C%5C%20%26%26%5Cmathsf%7Bcos%5C%2C%5Ctheta%3D%5Csqrt%7B1-x%5E2%7D%5Cqquad%5Ccheckmark%7D%5C%5C%5C%5C%5C%5C%20%26%26%5Ctextsf%7Bbecause%20%7D%5Cmathsf%7Bcos%5C%2C%5Ctheta%7D%5Ctextsf%7B%20is%20positive%20for%20%7D%5Cmathsf%7B%5Ctheta%5Cin%20%5Cleft%5B%5Cdfrac%7B%5Cpi%7D%7B2%7D%2C%5C%2C%5Cdfrac%7B%5Cpi%7D%7B2%7D%5Cright%5D.%7D%20%5Cend%7Barray%7D)
So the integral

becomes

Integrate

by parts:


Substitute back for the variable x, and you get

I hope this helps. =)
Tags: <em>integral inverse sine function angle arcsin sine sin trigonometric trig substitution differential integral calculus</em>