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ELEN [110]
3 years ago
9

Please help me with this!

Mathematics
1 answer:
stich3 [128]3 years ago
7 0

Answer:

y = x^2 - 4x - 6.

Step-by-step explanation:

The roots are  2 + √10 and 2 - √10, so in factor form we have:

(x -  (2 + √10))(x - (2 - √10))

= ( x -  2 - √10)(x - 2 + √10)

= x^2 - 2x + √10x - 2x + 4 - 2√10 - √10x  + 2√10 - √100

=  x^2 -4x + 4 - 10

= x^2 - 4x - 6.

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Please help me. alg 2<br><br> Find the common ratio of the geometric sequence -13, 39, -117
grandymaker [24]

Answer:

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Step-by-step explanation:

you can divide the second term by the first term to solve

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then,  I like to check that this fits with the third term

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A university is trying to determine what price to charge for tickets to football games. At a price of ​$ per​ ticket, attendance
Anika [276]

This question is incomplete, the complete question is;

A university is trying to determine what price to charge for tickets to football games. At a price of ​$24 per​ ticket, attendance averages 40,000 people per game. Every decrease of ​$4 adds 10,000 people to the average number. Every person at the game spends an average of ​$4 on concessions. What price per ticket should be charged in order to maximize​ revenue? How many people will attend at that​ price?

Answer:

a) price per ticket = $18

b) 55,000 will attend at that price

Step-by-step explanation:

Given that;

price of ticket = $24

so cost of ticket = 24 - x

every decrease of $4 adds 10,000 people

for $1 adds 2,500 people

Total people = 40000 + 2500x

Revenue function = people × cost + people × 4

so

R(x) = (40000 + 2500x)(24 - x) + (40000 + 2500x)4

R(x) = 960,000 - 40000x + 60000x - 2500x² + 160,000 + 10000x

R(x) = 1120000 + 30000x - 2500x²

R(x) = -2500x² + 30000x + 1120000

now for maximum revenue; R'(x) is to zero

so

R'(x) = d/dx(  -2500x² + 30000x + 1120000 ) = 0

⇒ -5000x + 30000 + 0 = 0

⇒ -5000x + 30000 = 0

⇒ 5000x = 30000

x = 30000 / 5000

x = 6

R'(X) = -5000 < 0 ⇒ MAXIMUM

∴ Revenue is maximum at x = 6

so cost of ticket ;

price per ticket = (24 - x) = 24 - 6 = $18

so price per ticket = $18

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= 40000 + (2500 × 6)

= 40000 + 15,000

= 55,000

Therefore, 55,000 will attend at that price

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Answer:

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