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Yuliya22 [10]
3 years ago
15

What is 36 divided by 540 using partial quosient

Mathematics
2 answers:
iogann1982 [59]3 years ago
6 0

excuse the writing io used my mouse
so the aim is to find a simple factor thst when u multiply the divisoor by it si lower thatn the dividend
in this case i used 10 so 10*36=360
then u subtract 360 ( 540-360=180)from the dividend and record the ten which i did on right side of the attachment
then u find another factor that can now multiply 36 but be less that 180 i chose 5
5*36=180
180-180= 0
finally u jus add the factors that used which are the 10 and 5= 15
therefore 540/36 =15

Dimas [21]3 years ago
5 0

We have to evaluate

    =\frac{540}{36}

To find the Partial Quotient,

First we will 10nth Multiple of 36 which is =360.

Then after , Subtracting 360 from 540, which is equal to 180,we will find those multiple of 36 which is nearer to 180 or divides 180 exactly.

Find Quotient in each case.

→36 × 10=360

→36×  5 =180

---------------------

→36 ×(10+5)=360+180

→36 × 15=540

⇒Partial Quotient=10+5=15

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b) The function velocity of particle Q is determined by the <em>derivative</em> formula for the division between two functions, that is:

v_{Q}(t) = \frac{f'(t)\cdot g(t)-f(t)\cdot g'(t)}{g(t)^{2}} (3)

Where:

  • f(t) - Function numerator.
  • g(t) - Function denominator.
  • f'(t) - First derivative of the function numerator.
  • g'(x) - First derivative of the function denominator.

If we know that f(t) = \sin \pi t, g(t) = 2 - t, f'(t) = \pi \cdot \cos \pi t and g'(x) = -1, then the function velocity of the particle is:

v_{Q}(t) = \frac{\pi \cdot \cos \pi t \cdot (2-t)-\sin \pi t}{(2-t)^{2}}

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|\dot r_{Q/P}| = \sqrt{\left(\frac{4}{9} \right)^{2}+(-4)^{2}}

|\dot r_{Q/P}| = \frac{4\sqrt{82}}{9}

The rate of change of the distance between particle P and particle Q at time t = \frac{1}{2} is \frac{4\sqrt{82}}{9}. \blacksquare

<h3>Remark</h3>

The statement is incomplete and poorly formatted. Correct form is shown below:

<em>Particle </em>P<em> moves along the y-axis so that its position at time </em>t<em> is given by </em>y(t) = 4\cdot t - 23<em> for all times </em>t<em>. A second particle, </em>Q<em>, moves along the x-axis so that its position at time </em>t<em> is given by </em>x(t) = \frac{\sin \pi t}{2-t}<em> for all times </em>t \ne 2<em>. </em>

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<em>a)</em><em> As times approaches 2, what is the limit of the position of particle </em>Q?<em> Show the work that leads to your answer. </em>

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<em>b) </em><em>Show that the velocity of particle </em>Q<em> is given by </em>v_{Q}(t) = \frac{2\pi\cdot \cos \pi t-\pi\cdot t \cdot \cos \pi t +\sin \pi t}{(2-t)^{2}}<em>.</em>

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<em>c)</em><em> Find the rate of change of the distance between particle </em>P<em> and particle </em>Q<em> at time </em>t = \frac{1}{2}<em>. Show the work that leads to your answer.</em>

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