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Wittaler [7]
3 years ago
7

HEllllppppppppoop!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Vaselesa [24]3 years ago
8 0
Inside of the square root should be "9+64".
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What is the intersection of x+2y=-4 and 4x=3x+12? And what do i do to find this out?
Andrews [41]
Clean up the equation with x first and x=12.
Substitute this value in to the other equation to solve for y.
You should get a solution of (12,-8)
4 0
3 years ago
Of the last 100 customers entering a computer shop, 25 have purchased a computer. If the classical method for computing probabil
SOVA2 [1]

Answer:

0.50

Step-by-step explanation:

The question asks you to apply the classical method of computing probability. In this method, prior events do not interfere in the likelihood of an event happening in the future, instead it states that every possible outcome is equally likely to happen.

In this case there are only two possible outcomes: purchase or not purchase a computer. Therefore, the likelihood that the next customer will purchase a computer is 50% or 0.50.

8 0
4 years ago
1. Chandler has a large and varied comic book collection. Of his
NeTakaya

Answer:

8/45

Step-by-step explanation:

Take the fraction that are superhero comics and multiply by the fraction of superhero comics that are Arachna comics

4/5 * 2/9

8/45

6 0
3 years ago
Use the zero product property to find the solutions to the equation 2x2 + x – 1 = 2.
FromTheMoon [43]

2 {x}^{2} + x - 1 = 2

Subtract sides -2

2 {x}^{2} + x - 1 - 2 = 2 - 2

2 {x}^{2} + x - 3 = 0

(x - 1)(2x + 3) = 0

_________________________________

x - 1 = 0

x = 1

##############################

2x + 3 = 0

x =  -  \frac{3}{2}  \\

_________________________________

Done♥️♥️♥️♥️♥️

3 0
3 years ago
Evaluate the expression under the given conditions. cos(θ − ϕ); cos θ = 3 5 , θ in quadrant iv, tan ϕ = − 15 , ϕ in quadrant ii
GaryK [48]
Begin with  cos(θ) = 5/13, θ in Quadrant IV 

you should distinguish the 5-12-13 right-angled triangle 

and then cosØ = adjacent/hypotenuse 

x = 5, r = 13 , y = -12, since Ø is in IV 

and sinØ = -12/13 


also tan(ϕ) = −√15 = -√15/1 = y/x and ϕ is in II, 

y = √15 , x = -1 

r^2 = x^2 + y^2 = 15+1 = 16 

r = 4 

sinϕ = √15/4 , cosϕ = -1/4 
you must know that: 

cos(θ − ϕ) = cosθcosϕ + sinθsinϕ 

= (5/13)(-1/4) + (-12/13)(√15/4) 

= -5/52 - 12√15/52 

= (-5-12√15)/52 
7 0
3 years ago
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