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3 years ago

Which certificate does Jenny require?

Mathematics

1 answer:

Airida [17]3 years ago

7 0

Can you give some more details please thank you

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Is the following relation a function?<br><br> {(3, −2), (1, 2), (−1, −4), (−1, 2)}

mel-nik [20]

Answer:

<h2>It's not a function.</h2>

Step-by-step explanation:

A function is a process or a relation that associates each element x of a set X, to a single element y of another set Y.

We have:

{(3, -2), (1, 2), (-1, -4), (-1, 2)}

for x = -1 are two values of y = -4 and y = 2. Therefore this realtion is not a function.

3 0

3 years ago

Read 2 more answers

Is y=3/4x proportional?

strojnjashka [21]

Answer:

My answer is Yes

Step-by-step explanation:

5 0

3 years ago

What is the equation of a circle whose center at (-5, -2) and radius is 2?

aliya0001 [1]

The equation of a circle whose centre ( $-5,-2$ ) and radius $2$ is $x^{2}+y^{2}+10x+4y+25=0$

What is equation of a circle?

A circle is a closed curve drawn from a fixed point called centre of the circle. The distance between the centre of the circle and the arc of the circle is called the radius of the circle.

The equation of a circle with centre $(h, k)$ radius $r$ is

$(x-h)^{2} +(y-k)^{2}=r^{2}$

Given center = $(-5,-2)$ and Radius = $2$

Put the Given value in the equation:

= $(x-(-5))^{2} +(y-(-2))^{2} = 2^{2}$

= $(x+5)^{2} +(y+2)^{2}=2^{2}$

= $(x^{2} +10x+25)+(y^{2}+4y+4)= 4$

= $x^{2} +y^{2}+10x+ 4y+ 29 = 4$

= $x^{2} +y^{2}+10x +4y+ 29-4=0$

= $x^{2} +y^{2}+10x+4y+25=0$

So, the equation of the circle whose centre is $(-5,-2)$ and Radius $2$ is

$x^{2}+y^{2}+10x+4y+25=0$

To read more about the equation of a circle. you can follow:

brainly.com/question/351704

#SPJ2

6 0

2 years ago

Hellllllllllllllllllllllllllp

Evgen [1.6K]

Answer:

f. I and IV only

Step-by-step explanation:

i hope this helps :)

5 0

3 years ago

What is the value of the square root of 2 to the third decimal place?

Pavel [41]

Answer:

1.414

Step-by-step explanation:

4 0

3 years ago