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almond37 [142]
3 years ago
9

Over time coral buried by sediments can turn into

Chemistry
1 answer:
MA_775_DIABLO [31]3 years ago
3 0
Granite  hope this help
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Is this example of a direct proportion or an inverse proportion?
ivanzaharov [21]

Answer:

Inverse proportion occurs when one value increases and the other decreases. For example, more workers on a job would reduce the time to complete the task. They are inversely proportional.

6 0
3 years ago
Predict whether the equilibria I) CH4(g) + H2O(g) ⇀↽ CO(g) + 3 H2(g), ∆H◦ = +206 kJ II) 2 SO2(g) + O2 ⇀↽ 2 SO3(g), ∆H◦ = −198 kJ
Dima020 [189]

Answer:

(1) I shifts toward product and II shifts toward reactant.

Explanation:

Increasing the temperature of an endothermic reaction (∆H is positive) shifts the equilibrium position to the right thus favoring product formation.

Increasing the temperature of an exothermic reaction (∆H is negative) shifts the equilibrium position to the left thus favoring the backward reaction.

3 0
3 years ago
How do you find the # of sigma and pi bonds using a Lewis dot structure
Lubov Fominskaja [6]

Every single bond is a sigma bond.

A double bond contains 1 sigma bond and 1 pi bond.

A triple bond contains 1 sigma bond and 2 pi bonds.


For example, in acetylene, H-C≡C-H, the sigma bond is formed by the head-on overlap of two sp orbitals. The pi bonds are formed by the side-on overlap of 2p orbitals.

3 0
3 years ago
Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibrium described by the equation N2O4(g)
lora16 [44]

<u>Answer:</u> The value of equilibrium constant is 0.997

<u>Explanation:</u>

We are given:

Percent degree of dissociation = 39 %

Degree of dissociation, \alpha = 0.39

Concentration of N_2O_4, c = \frac{1mol}{1L}=1M

The given chemical equation follows:

                     N_2O_4\rightleftharpoons 2NO_2

<u>Initial:</u>                c             -

<u>At Eqllm:</u>         c-c\alpha      2c\alpha

So, equilibrium concentration of N_2O_4=c-c\alpha =[1-(1\times 0.39)]=0.61M

Equilibrium concentration of NO_2=2c\alpha =[2\times 1\times 0.39]=0.78M

The expression of K_{c} for above equation follows:

K_{c}=\frac{[NO_2]^2}{[N_2O_4]}

Putting values in above equation, we get:

K_{c}=\frac{(0.78)^2}{0.61}\\\\K_{c}=0.997

Hence, the value of equilibrium constant is 0.997

4 0
3 years ago
If 11.2 g of naphthalene, C10H8, is dissolved in 107.8 g of chloroform, CHCl3, what is the molality of the solution?
Art [367]

Answer: 0.811m

Explanation: Molarity is the moles of solute present per kg of solvent.

Molar mass of C10H8 = . 128.17 g/mol

No. of moles = given mass/molar mass

11.2g C10H8 = 11.2/128.17 g/mol C10H8

= 0.0874 mol C10H8

NOW 107.8g solvent (chloroform) contains 0.0879 molecules (naphthalene)

1000g   ''    will contain (0.0879/107.8 x 1000) mole solute

= 0.811 mole

Molarity of the solution is 0.811 m (option A)

5 0
3 years ago
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