Answer:
Inverse proportion occurs when one value increases and the other decreases. For example, more workers on a job would reduce the time to complete the task. They are inversely proportional.
Answer:
(1) I shifts toward product and II shifts toward reactant.
Explanation:
Increasing the temperature of an endothermic reaction (∆H is positive) shifts the equilibrium position to the right thus favoring product formation.
Increasing the temperature of an exothermic reaction (∆H is negative) shifts the equilibrium position to the left thus favoring the backward reaction.
Every single bond is a sigma bond.
A double bond contains 1 sigma bond and 1 pi bond.
A triple bond contains 1 sigma bond and 2 pi bonds.
For example, in acetylene, H-C≡C-H, the sigma bond is formed by the head-on overlap of two sp orbitals. The pi bonds are formed by the side-on overlap of 2p orbitals.
<u>Answer:</u> The value of equilibrium constant is 0.997
<u>Explanation:</u>
We are given:
Percent degree of dissociation = 39 %
Degree of dissociation,
= 0.39
Concentration of
, c = 
The given chemical equation follows:

<u>Initial:</u> c -
<u>At Eqllm:</u>

So, equilibrium concentration of ![N_2O_4=c-c\alpha =[1-(1\times 0.39)]=0.61M](https://tex.z-dn.net/?f=N_2O_4%3Dc-c%5Calpha%20%3D%5B1-%281%5Ctimes%200.39%29%5D%3D0.61M)
Equilibrium concentration of ![NO_2=2c\alpha =[2\times 1\times 0.39]=0.78M](https://tex.z-dn.net/?f=NO_2%3D2c%5Calpha%20%3D%5B2%5Ctimes%201%5Ctimes%200.39%5D%3D0.78M)
The expression of
for above equation follows:
![K_{c}=\frac{[NO_2]^2}{[N_2O_4]}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BN_2O_4%5D%7D)
Putting values in above equation, we get:

Hence, the value of equilibrium constant is 0.997
Answer: 0.811m
Explanation: Molarity is the moles of solute present per kg of solvent.
Molar mass of C10H8 = . 128.17 g/mol
No. of moles = given mass/molar mass
11.2g C10H8 = 11.2/128.17 g/mol C10H8
= 0.0874 mol C10H8
NOW 107.8g solvent (chloroform) contains 0.0879 molecules (naphthalene)
1000g '' will contain (0.0879/107.8 x 1000) mole solute
= 0.811 mole
Molarity of the solution is 0.811 m (option A)