Answer:
a=-30
Step-by-step explanation:
Let
P(h)= probability of selecting heart = 13/52= 1/4
similarly
P(s)= probability of selecting spade =1/4
P(c)= probability of selecting club =1/4
P(d)= probability of selecting diamond =1/4
a)
P(h or s)= P(h)+P(s)= 1/4+1/4=2/4=1/2=0.5
b)
P(h or s or c)=P(h)+P(s)+P(c)=1/4+1/4+1/4=3/4=0.75
c)
P(2 or a diamond)=n(2heart, 2spade,2club,13 diamonds)/total number of cards
=(1+1+1+13)/52=16/52=4/13=0.3
or we could solve it as follows:
P(2 or a diamond)=P(2)+P(diamond)-P(2diamond)=4/52 + 13/52 + 1/52 = (4+13-1)/52=16/52=0.3
Answer:
Option D: g = 7 and h = 3
Step-by-step explanation:
The polynomial is;
8x² – 8x + 2 – 5 + x
Simplifying this gives;
8x² - 7x - 3
If this is simplified to 8x² – gx – h
Thus, by comparison of terms;
– gx = - 7x
-x will cancel out to get;
g = 7
Similarly, - h = - 3
Thus,h = 3
Therefore; g = 7 and h = 3
The probability of finding a substandard weld is: p = 5% =
0.05 <span>
We are given that the sample size: n = 300
Using the Poisson Distribution , the average number of welds (m) is:</span>
m = n*p =
m = 300 * 0.05 <span>
m =15 </span>
<span>
The standard deviation of welds (s) is calculated by:</span>
s = sqrt (m)
s = sqrt (15)
s = 3.873
<span>
<span>Assuming normal distribution, the z value corresponding to 30
sub standards is:
z =( X - Mean) / standard deviation
z =(30 - 15) / 3.873
z = 15 / 3.873
z = 3.87</span></span>
<span>
<span>The z value based on the standard normal curves has a maximum
value of 3.49. Beyond that z value of 3.49 would mean exceeding 100%. Therefore
z = 3.87 is not normal and definitely it is unusual to find 30 or more
substandard.</span></span>
4k+5+ 6k + 10 = 115
10k + 15 = 115
10k = 100
K = 10°
