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Andrew [12]
3 years ago
12

: Matteo has only $62.50 to spend at a soccer store. He wants to buy a jersey that costs $27.50 including tax, and socks that co

sts $3.50 each pair, including tax. ​ ​Choose an equation to determine x, the maximum number of socks Matteo could buy.
Mathematics
1 answer:
Anastasy [175]3 years ago
3 0

Answer:

Step-by-step explanation:

$62.50                              $35.00/ $3.50 = 10

-$27.50                               x=10

-------------

$35.00

Matteo can buy a maximum of 10 socks.

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4 x 2 tens = 80, 28 x 14 = 392
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What is the linear function equation represented by the graph?
igor_vitrenko [27]

Look at the picture.

The point-slope form of a line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (0, 1) and (2, 0). Substitute:

m=\dfrac{0-1}{2-0}=\dfrac{-1}{2}=-\dfrac{1}{2}\\\\y-1=-\dfrac{1}{2}(x-0)\\\\y-1=-\dfrac{1}{2}x\qquad|+1\\\\y=-\dfrac{1}{2}x+1

Answer: f(x)=-\dfrac{1}{2}x+1

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What are two possible FIRST STEPS to solve the equation below?<br> 3(x-5)=21
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Answer:

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Step-by-step explanation:

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3 years ago
Use Lagrange multipliers to find the maximum and minimum values of (i) f(x,y)-81x^2+y^2 subject to the constraint 4x^2+y^2=9. (i
sp2606 [1]

i. The Lagrangian is

L(x,y,\lambda)=81x^2+y^2+\lambda(4x^2+y^2-9)

with critical points whenever

L_x=162x+8\lambda x=0\implies2x(81+4\lambda)=0\implies x=0\text{ or }\lambda=-\dfrac{81}4

L_y=2y+2\lambda y=0\implies2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1

L_\lambda=4x^2+y^2-9=0

  • If x=0, then L_\lambda=0\implies y=\pm3.
  • If y=0, then L_\lambda=0\implies x=\pm\dfrac32.
  • Either value of \lambda found above requires that either x=0 or y=0, so we get the same critical points as in the previous two cases.

We have f(0,-3)=9, f(0,3)=9, f\left(-\dfrac32,0\right)=\dfrac{729}4=182.25, and f\left(\dfrac32,0\right)=\dfrac{729}4, so f has a minimum value of 9 and a maximum value of 182.25.

ii. The Lagrangian is

L(x,y,z,\lambda)=y^2-10z+\lambda(x^2+y^2+z^2-36)

with critical points whenever

L_x=2\lambda x=0\implies x=0 (because we assume \lambda\neq0)

L_y=2y+2\lambda y=0\implies 2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1

L_z=-10+2\lambda z=0\implies z=\dfrac5\lambda

L_\lambda=x^2+y^2+z^2-36=0

  • If x=y=0, then L_\lambda=0\implies z=\pm6.
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We have f(0,0,-6)=60, f(0,0,6)=-60, f(0,-\sqrt{11},-5)=61, and f(0,\sqrt{11},-5)=61. So f has a maximum value of 61 and a minimum value of -60.

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3 years ago
Show all work to factor x4 – 17x2 + 16 completely.
denis23 [38]

Answer:

(x - 4)(x + 4)(x - 1)(x + 1)

Step-by-step explanation:

Given

x^{4} - 17x² + 16

Use the substitution u = x², then

u² - 17u + 16

Consider the factors of the constant term (+ 16) which sum to give the coefficient of the u- term (- 17)

The factors are - 16 and - 1, then

u² - 17u + 16

= (u - 16)(u - 1) ← replace u by x²

= (x² - 16)(x² - 1) ← both factors are difference of squares

= (x - 4)(x + 4)(x - 1)(x + 1)

4 0
3 years ago
Read 2 more answers
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