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vekshin1
3 years ago
12

Nononononononononono

Mathematics
2 answers:
Burka [1]3 years ago
8 0

Answer:

yesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyesyes

Andrews [41]3 years ago
3 0

Answer:

yesyesyesyes

Step-by-step explanation:

yesyesyesyesyes

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Please I need serious help with this ASAP!!! I will mark brainliest if correct!! Please explain!!!
allsm [11]

Answer:

1. Given

2. Reflection property of congruence

3. Definition of a a midpoint

4. Reflexive property of congruence

5. CPCTC

Step-by-step explanation:

3 0
3 years ago
Find the exact area of a circle with a diameter of 5 yards. Use 3.14 for π​
Vlada [557]

Answer:

19.634595408

Step-by-step explanation:

I think this because

πr^2 is how u get area I'd a circle

all u have to do is plug it in

6 0
3 years ago
ΔABC with vertices A(-3, 0), B(-2, 3), C(-1, 1) is rotated 180° clockwise about the origin. It is then reflected across the line
hjlf

Answer: The answer would be C. Please give me a thanks :) bye!

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)
UkoKoshka [18]

Since the limit becomes the undetermined form

\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}

it means that both polynomials have a root at x=1. So, we can fact both numerator and denominator:

x^3-2x^2+3x-2 = (x-1)(x^2-x+2)

2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)

So, the fraction becomes

\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}

Now, as x approaches 1, you have no problems anymore:

\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}

4 0
3 years ago
The time to fly between new york city and chicago is uniformly distributed with a minimum of 120 minutes and a maximum of 150 mi
Paul [167]
120+150=270
270÷2=135
Mean=135
5 0
3 years ago
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