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4 years ago

Which relation is a function

Mathematics

1 answer:

siniylev [52]4 years ago

6 0

The first option is a function as it passes the vertical line test and as each domain (x value) is paired with exactly one range (y value)

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Solve the system of equations. \begin{aligned} & -10x+3y = 5 \\\\ & x=y-4 \end{aligned} −10x+3y=5 x=y−4

Ksenya-84 [330]

Answer:

x = 1

y = 5

Step-by-step explanation:

You can use either substitution or elimination for this problem. I will use substitution.

Step 1: Replace x in the 1st equation

-10(y-4) + 3y = 5

-10y + 40 + 3y = 5

-7y = -35

y = 5

Step 2: Plug <em>y </em>into an original equation to find <em>x</em>

x = 5 - 4

x = 1

And you have your final answers!

7 0

3 years ago

There are 18 gallons of gas in a car at the

GREYUIT [131]

Answer:

18/2.5 = 7.2

Step-by-step explanation:

Since there are 18 gallons at the beginning of the trip you divide by 2.5 to find out how much gas is left after each hour.

7 0

2 years ago

Samantha believes that the probability of her winning the gymnastics meet is 3/8.

Citrus2011 [14]

the answer would be 5/8. the probablities of her winning or losing should add up to 8/8.

8/8 - 3/8 would be 5/8.

hope that helps!

6 0

3 years ago

Need help! will mark brainliest

bixtya [17]

Step-by-step explanation:

run a 9.8 meter dash,bowled 5 strikes in sports,basketball game,snacks

4 0

3 years ago

For her birthday, Monica can invite 6 of her 15 student friends to join her at a theme park. If she chooses to invite friends at

svlad2 [7]

Answer:

B. 1 out of 5,005

Step-by-step explanation:

Given

Number of Friends = 15

Required

Probability of selecting 6 friends

The first step is to calculate the number of ways 6 friends can be selected

The keyword in the above statement is selection;

This implies combination;

The number of ways is calculated as follows;

$\left[\begin{array}{c}n&r&\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 15 and r = 6

$\left[\begin{array}{c}n&r&\end{array}\right] = \frac{n!}{(n-r)!r!}$

becomes

$\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15!}{(15-6)!6!}$

$\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15!}{9!6!}$

$\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15 * 14 * 13 * 12 * 11 *10 * 9!}{9! *6 * 5 * 4 * 3 * 2 * 1}$

$\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15 * 14 * 13 * 12 * 11 *10}{6 * 5 * 4 * 3 * 2 * 1}$

$\left[\begin{array}{c}15&6&\end{array}\right] = \frac{3603600}{720}$

$\left[\begin{array}{c}15&6&\end{array}\right] =5005$

Hence, there are 5005 ways of selecting 6 from 15 friends

Since, there's only one way of selecting the 6 named friends

Then, the probability is 1 out of 5,005

3 0

3 years ago