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3 years ago

Can the sides of a triangle have lengths 3, 6, and 14?

Mathematics

2 answers:

dmitriy555 [2]3 years ago

8 0

Answer:

Not a right triangle

Step-by-step explanation:

In a right triangle this statement is always true:

$A^{2} +B^{2} =C^{2}$

$3^{2} +6^{2} \neq 14^{2}$

There for it isn't a right triangle.

Hope this helps.

<em>plz mark me brainliest. :)</em>

fomenos3 years ago

7 0

Answer:

No, the first two numbers have to be more than the last number when added up.

Step-by-step explanation:

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7 0

3 years ago

Find an equation for the line with the given properties. Perpendicular to the line x - 6y = 8; containing the point (4,4) O 1) y

Pepsi [2]

Answer:

Option 3 - $y=-6x+28$

Step-by-step explanation:

Given : Perpendicular to the line $x - 6y = 8$ ; containing the point (4,4).

To Find : An equation for the line with the given properties ?

Solution :

We know that,

When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.

Slope of the equation $x - 6y = 8$

Converting into slope form $y=mx+c$ ,

Where m is the slope.

$y=\frac{x-8}{6}$

$y=\frac{x}{6}-\frac{8}{6}$

The slope of the equation is $m=\frac{1}{6}$

The slope of the perpendicular equation is $m_1=-\frac{1}{m}$

The required slope is $m_1=-\frac{1}{\frac{1}{6}}$

$m_1=-6$

The required equation is $y=-6x+c$

Substitute point (x,y)=(4,4)

$4=-6(4)+c$

$4=-24+c$

$c=28$

Substitute back in equation,

$y=-6x+28$

Therefore, The required equation for the line is $y=-6x+28$

So, Option 3 is correct.

8 0

3 years ago

Decide whether each table could represent a proportional relationship. If the

Ymorist [56]

Answer:

Step-by-step explanation:

If given tables in the picture show the proportional relationship,

Number of wheels (w) ∝ Number of buses (b)

w ∝ b

w = kb

Here, k = proportionality constant

k = $\frac{w}{b}$

Number of buses (b) Number wheels (w) Wheels per bus $(\frac{w}{b})$

5 30 $\frac{30}{5}=6$

8 48 $\frac{48}{8}=6$

10 60 $\frac{60}{10}=6$

15 90 $\frac{90}{15}=6$

Here, proportionality constant is 6.

Similarly, If number of wheels (w) ∝ Number of train cars (t)

w = kt

Here, k = proportionality constant

k = $\frac{w}{t}$

Number of train cars(t) Number of wheels(w) Wheels per train car ( $\frac{w}{t}$ )

20 184 $\frac{184}{20}=9.2$

30 264 $\frac{264}{30}=8.8$

40 344 $\frac{344}{40}=8.6$

50 424 $\frac{424}{50}=8.48$

Since, ratio of w and t is not constant, relation between number of wheels and number of train cars is not proportional.

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3 years ago