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3 years ago

Can the sides of a triangle have lengths 3, 6, and 14?

Mathematics

2 answers:

dmitriy555 [2]3 years ago

8 0

Answer:

Not a right triangle

Step-by-step explanation:

In a right triangle this statement is always true:

$A^{2} +B^{2} =C^{2}$

$3^{2} +6^{2} \neq 14^{2}$

There for it isn't a right triangle.

Hope this helps.

plz mark me brainliest. :)

fomenos3 years ago

7 0

Answer:

No, the first two numbers have to be more than the last number when added up.

Step-by-step explanation:

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What use the perimeter of the figure below

morpeh [17]

Answer:

Step-by-step explanation:

The perimeter would be 2*(4(2x+1) + 3(x+4)) because the right side length and the top side length are known. The left side length must equal the right side length and the bottom side length must equal the top side length. So the answer must be:

2*(4(2x+1) + 3(x+4)) = 2*(8x+4+3x+12) = 2*(11x+16) = 22x+32

C. 22x+32

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3 years ago

Ok so math questions:

dolphi86 [110]

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3 years ago

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AVprozaik [17]

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4 years ago

What is the area of each of the following rhombuses ?

MAVERICK [17]

Answer:

Area of rhombus is 105.84 cm².

Step-by-step explanation:

Area of rhombus is given by

Area = diagonal ¹ × diagonal ² / 2
= 8.4 + 8.4 × 6.3 + 6.3 / 2
= 16.8cm × 12.6 cm /2
= 211.68 cm²/2
= 105.84 cm²

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3 years ago

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(s^3−2s−9)+(2s^2−6s^3+s) = s^4-6s^3+2s^2-2s What Am I getting Wrong Here?

sleet_krkn [62]

Omg ur profile picture and fo the question properly

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3 years ago