Answer:
The answer to this question is given below in the explanation section.
Explanation:
The correct option to this question is:
.clr{color:blue;}
I write the complete code of HTML using this CSS style to execute this scenario as given below
<html>
<head>
<style>
.clr
{
color:blue;
}
</style>
</head>
<body>
<a href="pg.html" class="clr">click here</a>
<h2 class="clr">Home</h2>
</body>
</html>
The bold text is a complete code of this question. When you will run it it will execute a link and Home text on the page in blue color. So the correct option is .clr{color:blue;}
Answer:
Easy peasy, if you open Microsoft word and you click up at the top and you click the symbol as shown in A, then you click on inserted tab it will show up as B which is → symbol
So the answer is B →.
Answer:
\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\
Explanation:
It is easy to understand. Algorithm is a step-wise representation of a solution to a given problem. In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program
Algorithms are time-consuming. Big tasks are difficult to put in algorithms. Difficult to show branching and looping in algorithms. Understanding complex logic through algorithms can be very difficult.
Answer:
Explanation:
#include <iostream>
using namespace std;
int main ()
{
int responses[30],count[6];
int score = 0;
string resp = " ";
for (int i = 0; i < 30; i++)
{
responses[i] = 0;
}
for (int i = 0; i < 6; i++)
{
count[i,1]=0;
count[i,2]=0;
count[i,0]=0;
}
while ((resp != "Y") && (resp != "y"))
{
for (int i = 0; i < 30; i++)
{
while ((score > 5) || (score < 1))
{
cout << "Student " << (i+1)<< " please enter a value (1-5):";
cin >> score;
}
responses[i] = score;
if((score > 5)||(score<1))
{
if(score==1) count[1]++;
if(score==2) count[2]++;
if(score==3) count[3]++;
if(score==4) count[4]++;
if(score==5) count[5]++;
}
score = 0;
}
cout<< "Response Frequency Percentage"<<endl;;
cout<< " 1 "<<count[1]<<" "<<(count[1]/30)<<"%"<<endl;
cout<< " 2 "<<count[2]<<" "<<(count[2]/30)<<"%"<<endl;
cout<< " 3 "<<count[3]<<" "<<(count[3]/30)<<"%"<<endl;
cout<< " 4 "<<count[4]<<" "<<(count[4]/30)<<"%"<<endl;
cout<< " 5 "<<count[5]<<" "<<(count[5]/30)<<"%"<<endl;
cout<< "Do you want to exit? Press Y to exit any other key to continue: ";
cin>> resp;
}
return 0;
}
