Question

(Print distinct numbers) Write a program that reads in integers separated by a space in one line and displays distinct numbers in their input order and separated by exactly one space (i.e., if a number appears multiple times, it is displayed only once). Hint: Read all the numbers and store them in list1. Create a new list list2. Add a number in list1 to list2. If the number is already in the list, ignore it.

Answer 1

Answer:

Following are the program to the given question:

num = input("Enter numbers: ")#defining a variable num for input value  

list1 = num.split()#defining a list1 that adds value in list1  

list2 = []#defining an empty list list2

for j in range(len(list1)):#defining a for loop that checks the list value in range  

   if not list1[j] in list2:# use if block that checks multiple value

       list2.append(list1[j])#add value in list2

print("The distinct numbers are: ")#print message

for j in range(len(list2)):#defining for loop for print list value

   print(list2[j])#print list value

Output:

Enter numbers: 1 22 55 7 22 1 1 2 3

The distinct numbers are:  

1

22

55

7

2

3

Explanation:

In the above-code, a "num" variable is defined, that takes inputs from the console screen, and in the next step, "list1 and list2" is defined. In the "list1" it adds num variable value a into the list.

In the next step, a for loop is defined that checks the list value in range , and define an if block, that checks multiple value and add value into the list2, and in the next step, the for loop is defined that prints the list2 values.