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artcher [175]
4 years ago
13

When is it easiest to determine the percent of a number using a fraction? Using a decimal?

Mathematics
1 answer:
Katen [24]4 years ago
8 0

it's easier to use a decimal

percent means parts out of 100

x/100=x%


if you have a decimal, just move the decimal place to the left 2 places

if you have a fraction, try to get the denomenator equal to 100, or divide it out and move the decimal place to the left 2 places



using a decimal is easier to find percent

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Explain, in words, how to find -4(-1.5) using a number line. Where do you end up?
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3 years ago
Can someone plz help me
Goshia [24]

Answer:

Your table might look something like this:

The dads steps:

3

6

9

12

15

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Sons steps:

5

10

15

20

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You can notice the pattern. If dad walks 3 steps, son walks 5. If dad walks another 3, son walks another 5. And so on. This means dad walks 12 steps when the sin walks 20 steps.

Step-by-step explanation:

The ratio is 3:5. This means dad wlaks 3 steps so son must walk 5 steps basically. So.......... You can now create the table. Y I just have to multiply or divide each side ( of the colon:) so. Whatever you do to one side, you do to the other side. If you x3 on one side, you do it to other. Same goes for division. In the 'table' I did above, I x2 to get 6 and 10. Then I took the 3 and the 5 again and timsed those by 3. You can also change the 6 and the 10. So:

3:5

Then x2

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Then I take the top layer (you can either choose to change the top layer, or layer above as long as you do the same thing to each side. Remember, only x and ÷. No + or-.) and I x3

9:15

Then I could take 9 and 15 and x5

45:75

It's crazy that all these. Ratios mena the same thing! 45 steps from dad would take the son 75 steps. You can also divide the last ratio of 45:75 to find the one you started with, 3:5.

So you get the idea.

It is probably best to do what I did in the table in the answer part because I did a pattern. Take the top layer, and x2, then x3, then x4, ect. Rather then doing random things.

5 0
4 years ago
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