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DENIUS [597]
4 years ago
12

We call the part or the remaining number in a percent problem the?

Mathematics
1 answer:
ollegr [7]4 years ago
4 0
Amount, hope it helps (:
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What is the product of (–1.5)(0.8)
topjm [15]
The best answer would be -1.2 because when you multiply a negative by a positive, you always get a negative. Hope this helped!
8 0
4 years ago
Read 2 more answers
Given f(x) = 21 - 1, complete the missing values in the table
Anna11 [10]

Answer:

first one is f(x)=-5

second one is f(x)=7

third one is x=-3

4th one is x=0

5th one is f(x)=1

6th one is x=-4

Step-by-step explanation:

first one. plug in x as -2:

f(x)=2*-2-1=-4-1=-5

second one is the same way:

f(x)=4*2-1=8-1=7

third one is a different one:

2x-1=-7

2x=-6

x=-3

4th one is the same way:

2x-1=-1

2x=0

x=0

5th way is the same thing as previous:

f(x)=2*1-1=2-1=1

Finally, the 6th one is the same thing as the 4th one:

2x-1=-9

2x=-8

x=-4

Done!

6 0
2 years ago
Twice a number added to the product of 14 and 2 is 30. find the number<br>​
Molodets [167]
Answer: x = 1

Explanation:

Let x be the unknown number.

Thus:

2x + (14 • 2) = 30
2x + 28 = 30
2x = 30 - 28
2x = 2
x = 2/2
x = 1
8 0
3 years ago
Read 2 more answers
When two fractions refer to the same whole explain why the fraction with a lesser denominator has larger pieces than the fractio
dexar [7]
Because there are less pieces the whole is split up into. For instance, if you have 1 bag of cookies, you would get more cookies per person if it was split between 2 people than if it was split between 10, because each person gets more of the whole, and there's less people to split up that whole.
since you have an equal amount of pieces from each, the whole that was split into the least pieces, or the number with the smaller denominator will be larger since the pieces will be larger
3 0
4 years ago
Using the pattern, give the coefficients of (x + y)^5 and (x + y)^6
musickatia [10]

Answer:

(x+y)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5

(x+y)^6=x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

Step-by-step explanation:

In order to find the values of (x+y)^5 and (x+y)^6, you need to apply the binomial theorem (high-level math you most likely don't need to worry about, it's easier than multiplying all the binomials together).

(x+y)^5 = \sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i = \frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5 = x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5.

(x+y)^6 = \sum _{i=0}^6\binom{6}{i}x^{\left(6-i\right)}y^i = \frac{6!}{0!\left(6-0\right)!}x^6y^0+\frac{6!}{1!\left(6-1\right)!}x^5y^1+\frac{6!}{2!\left(6-2\right)!}x^4y^2+\frac{6!}{3!\left(6-3\right)!}x^3y^3+\frac{6!}{4!\left(6-4\right)!}x^2y^4+\frac{6!}{5!\left(6-5\right)!}x^1y^5+\frac{6!}{6!\left(6-6\right)!}x^0y^6= x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6.

5 0
3 years ago
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