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3 years ago

We call the part or the remaining number in a percent problem the?

Mathematics

1 answer:

ollegr [7]3 years ago

4 0

Amount, hope it helps (:

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A levee protects a town in a low-lying area from flooding. According to geologists, the banks of the levee are eroding (wearing

Cloud [144]

Answer:

The signed number that indicates how much of the levee will erode during the next decade is:

-30 feet

Step-by-step explanation:

a) Data and Calculations:

Erosion rate of the banks of the levee = 3 feet per year

For 10 years, if nothing is done to correct the problem, the eroded banks will be equal to 10 * 3 = 30 feet

Therefore, the signed erosion in the next decade is -30 feet.

b) The quantity of erosion can be given as the number of years involved without correction, multiplied by the rate of erosion per year. This implies that the quantity of erosion depends on the number of years and the rate of erosion per year.

5 0

3 years ago

Vivi is a drummer for a band. She burns 756756756 calories while drumming for 333 hours. She burns the same number of calories e

Blizzard [7]

Answer:

its 252 calories per hour

Step-by-step explanation:

I divided 756 by 3 to find the answer

3 0

3 years ago

For ten school days the numbers of bikes parked at a school bike rack are 10,12,8,11,13,9,2,1,9, and 12

kumpel [21]

Step-by-step explanation:

for this question is not even possible

6 0

3 years ago

5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

3 0

3 years ago

The price of a new dishwasher is £376. This price includes VAT at a rate of 17.5%. What was the price before VAT was added?

dsp73

£376=117.5% so (376/117.5)= 1% x 100= £320 is the original price

5 0

3 years ago