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nikdorinn [45]
2 years ago
7

Evaluate the function at the given values of the independent variable. Simplify the results.

Mathematics
1 answer:
wlad13 [49]2 years ago
8 0

answers \\ a. \:  \: 0 \\ b. \:  \:  \frac{ - 63}{8}  \\ c. \:  \:  {c}^{3}  -  {5c}^{2}  \\ d. \:  \:  {t}^{3}  + 25t +  {10t}^{2}  \\ please \: see \: the \: attached \: picture \\ for \: full \: solution \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment

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Find the area of square if the length of its diagonal is 18 cm​
NikAS [45]

Answer:

324

Step-by-step explanation:

5 0
2 years ago
A bag with 2 1/2 quarts of peanuts can make 2 1/6 jars of peanut butter. How many
diamong [38]

Answer:

You will need 3 6/13 quarts of peanuts to make 3 jars of peanuts butter

Step-by-step explanation:

To make this answering seamless, we make the mixed fractions into improper fractions

Hence 2 1/2 becomes 5/2

while 2 1/6 becomes 13/6

Here we are told that a bag with 5/2 quarts of peanuts can make 13/6 jars of peanuts butter

Hence, x quarts of peanuts will make 3 jars of peanuts butter

To get the value of x, what we simply need to do is to cross multiply.

Thus, we have

5/2 - 13/6

x - 3

3 * 5/2 = 13/6 * x

15/2 = 13x/6

26x = 90

x = 90/26

x = 45/13

x = 3 6/13

3 0
3 years ago
Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a
hram777 [196]

Answer:

(1,1)

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points (x_1,y_1)\,,\,(x_2,y_2) is equal to \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

So,

EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}

Perimeter of a figure is the length of its outline.

EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

Put (x,y)=(1,1)

\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9

This is true.

So, the point (1,1) satisfies the equation \sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

So, point H is (1,1).

7 0
3 years ago
Replacing only the minimum value in a data to a smaller number will change the median
irakobra [83]
This is false my dude.
5 0
3 years ago
Read 2 more answers
Barry read for 15 more minutes than Robert.
Greeley [361]
Hi!

C. v + 15

Barry read for 15 MORE minutes than Robert.
6 0
3 years ago
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