Evaluate 3(4-2)^2 :) :)

Svetach [21]

Answer :
<span>Unless we have a relationship defined between x and y there is no common factor apart from 1.
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hope it helps
~Reema

7 0

3 years ago

The correlation coefficient between two quantitative variables is approximately 0.6. What does the value of this correlation coe

murzikaleks [220]

Answer:

The model does not fits the data well.

Step-by-step explanation:

Correlation:

Correlation is a technique that help us to find or define a relationship between two variables.

It is a measure of linear relationship between two quantities.

A positive correlation means that an increase in one quantity leads to an increase in another quantity
A negative correlation means with increase in one quantity the other quantity decreases.

R-square, $R^2$

The quantity R-squared is an indicator of the predictive power of a model.
It explains the variation in the dependent variable due to independent variable.
It shows how well the model fits the data.
R-squared is also known as the coefficient of determination.

$R^2 = \text{(Correlation coefficient)}^2= (0.6)^2 = 0.36 = 36\%$

Therefore, only 36% of the variations in the dependent variable is explained by the independent variable in the model which means more than 50% of variation cannot still be explained in the dependent variable.

Hence, the model does not fits the data well.

8 0

4 years ago

In the equation m-1 1/3=4

romanna [79]

m = 5 $\frac{1}{3}$

note that 1 $\frac{1}{3}$ = $\frac{4}{3}$

isolate m by adding $\frac{4}{3}$ to both sides

m = 4 + $\frac{4}{3}$ = $\frac{16}{3}$ = 5 $\frac{1}{3}$

3 0

4 years ago

I need the answer for this asp.

TEA [102]

Answer:

This is Isosceles Right

Step-by-step explanation:

An Isosceles is a triangle that has two sides the same length and one side longer or shorter

An Right is an triangle with a 90˚

Hope this helps!

3 0

3 years ago

Read 2 more answers

A large pool of adults earning their first driver’s license includes 50% low-risk drivers, 30% moderate-risk drivers, and 20% hi

Mamont248 [21]

Answer:

The probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

Step-by-step explanation:

Denote the different kinds of drivers as follows:

L = low-risk drivers

M = moderate-risk drivers

H = high-risk drivers

The information provided is:

P (L) = 0.50

P (M) = 0.30

P (H) = 0.20

Now, it given that the insurance company writes four new policies for adults earning their first driver’s license.

The combination of 4 new drivers that satisfy the condition that there are at least two more high-risk drivers than low-risk drivers is:

S = {HHHH, HHHL, HHHM, HHMM}

Compute the probability of the combination {HHHH} as follows:

P (HHHH) = [P (H)]⁴

= [0.20]⁴

= 0.0016

Compute the probability of the combination {HHHL} as follows:

P (HHHL) = ${4\choose 1}$ × [P (H)]³ × P (L)

= 4 × (0.20)³ × 0.50

= 0.016

Compute the probability of the combination {HHHM} as follows:

P (HHHL) = ${4\choose 1}$ × [P (H)]³ × P (M)

= 4 × (0.20)³ × 0.30

= 0.0096

Compute the probability of the combination {HHMM} as follows:

P (HHMM) = ${4\choose 2}$ × [P (H)]² × [P (M)]²

= 6 × (0.20)² × (0.30)²

= 0.0216

Then the probability that these four will contain at least two more high-risk drivers than low-risk drivers is:

P (at least two more H than L) = P (HHHH) + P (HHHL) + P (HHHM)

+ P (HHMM)

= 0.0016 + 0.016 + 0.0096 + 0.0216

= 0.0488

Thus, the probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

6 0

4 years ago