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3 years ago

6

Cases are normally sold full. There were three partially full cases that could be combined to make full cases. The cases were 11

/16, 5/16 and 7/16 full.How many additional full cases can be sold?

1 answer:

Pani-rosa [81]3 years ago

3 0

You will get 1 7/16 cases

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sdas [7]

Answer:

a

$n= 75, 582$

b

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c

$n = 253$

Step-by-step explanation:

Generally the size of the sample sample space is mathematically represented as

$n = \left N } \atop {}} \right. C_r$

Where N is the total number of objects available and r is the number of objects to be selected

So for a, where N = 19 and r = 8

$n = \left 19 } \atop {}} \right. C_8 = \frac{19 !}{(19 - 8 )! 8!}$

$= \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}$

$n= 75, 582$

For b Where N = 25 and r = 3

$n = \left 25 } \atop {}} \right. C_3 = \frac{25 !}{(19 - 3 )! 3!}$

$= \frac{25 *24 *23 *22 ! }{22 ! \ 3!}$

$n= 2300$

For c Where N = 23 and r = 2

$n = \left 23 } \atop {}} \right. C_2 = \frac{23 !}{(23 - 2 )! 2!}$

$= \frac{23 *22 *21! }{21 ! \ 3!}$

$n = 253$

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djyliett [7]

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Step-by-step explanation:

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wlad13 [49]

Use the pythagorean theorm

16^2 + 12^2 = c^2
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Likurg_2 [28]

7/13 = about 0.54
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The answer is
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Answer:(A²-B²) = (A-B)² + 2AB

Step-by-step explanation:

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