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oee [108]
3 years ago
9

Part 2: Solve the system using the substitution method. Show all work here and indicate the solution for the system as an ordere

d pair.
Part 3: Solve the system using the addition method. Show all work here and indicate the solution for the system as an ordered pair.

x - 2y = 0 
5x + 2y = 24
Mathematics
1 answer:
Rom4ik [11]3 years ago
5 0
Substitution:

Step 1: Choose one of the two equations and solve for either x or y.

     x - 2y = 0
       + 2y  +2y
--------------------------
     x = 2y + 0 

Step 2: Plug in the value you got for x or y into the equation you did not work with in Step 1.

5(2y + 0) + 2y = 24
10y + 0 + 2y = 24
 
12y = 24
------- ------
  12    12

y = 2 

Step 3: Plug in the number you got for y into either equation.

     5x + 2(2) = 24
     5x + 4 = 24
          - 4    - 4
---------------------------
     5x = 20
   ------ ------
      5      5

x = 4

Your final answer should be written as a coordinate pair: (4,2).
____________________________________________________________

Elimination:

Add the two equations together to eliminate y.

     x - 2y = 0
+ 5x + 2y = 24
----------------------
   6x = 24
 ------ ------
    6      6

x = 4

Step 2: Substitute the x value into the original equation to find y.

5(4) + 2y = 24       20 + 2y = 24
                           - 20          - 20
                       --------------------------
                             2y = 4 
                           ------ -----
                              2     2
  
                             y = 2

I hope this answer helps you :D
                         

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jok3333 [9.3K]
Step 2 is wrong and i don't know the other question
6 0
3 years ago
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1/2(x + 1)²- 3
Ierofanga [76]

Answer:

  • a = 1/2
  • h = -1
  • k = -3

Step-by-step explanation:

We assume you want to compare your expression to the form ...

  a(x -h)² +k

  1/2(x +1)² +k

The multiplier outside parentheses is ...

  a = 1/2

The horizontal offset inside parentheses is ...

  -h = 1

  h = -1

The vertical offset outside parentheses is ...

  k = -3

4 0
3 years ago
A candle has been burning for 20 min and is now 25 cm tall. In an hour it will be 10 cm tall. Which equation models the height y
stiv31 [10]

Answer:

(y - 25) = - 0.25(x - 20)

Step-by-step explanation:

Given that :

Height of candle after burning for 20 minutes = 25 cm

Height after burning for 1 hr (60 minutes) = 10 cm

Height (y) in cm of candle x minutes after being lit:

Using the equation :

(y - y1) = m(x - x1)

m = (change in y / change in x)

Change in height within 60 minutes :

Height at 20 minutes = 25cm

Height after an hour = 10

Change in height per hour = (25 - 10) = 15cm

Hence, m = change in height per minute

15cm / 60 = 0.25cm ( - 0.25) (decrease in height)

y1 = 25 ; x1 = 20

(y - y1) = m(x - x1)

(y - 25) = - 0.25(x - 20)

4 0
3 years ago
Name/ Uid:1. In this problem, try to write the equations of the given surface in the specified coordinates.(a) Write an equation
Gemiola [76]

To find:

(a) Equation for the sphere of radius 5 centered at the origin in cylindrical coordinates

(b) Equation for a cylinder of radius 1 centered at the origin and running parallel to the z-axis in spherical coordinates

Solution:

(a) The equation of a sphere with center at (a, b, c) & having a radius 'p' is given in cartesian coordinates as:

(x-a)^{2}+(y-b)^{2}+(z-c)^{2}=p^{2}

Here, it is given that the center of the sphere is at origin, i.e., at (0,0,0) & radius of the sphere is 5. That is, here we have,

a=b=c=0,p=5

That is, the equation of the sphere in cartesian coordinates is,

(x-0)^{2}+(y-0)^{2}+(z-0)^{2}=5^{2}

\Rightarrow x^{2}+y^{2}+z^{2}=25

Now, the cylindrical coordinate system is represented by (r, \theta,z)

The relation between cartesian and cylindrical coordinates is given by,

x=rcos\theta,y=rsin\theta,z=z

r^{2}=x^{2}+y^{2},tan\theta=\frac{y}{x},z=z

Thus, the obtained equation of the sphere in cartesian coordinates can be rewritten in cylindrical coordinates as,

r^{2}+z^{2}=25

This is the required equation of the given sphere in cylindrical coordinates.

(b) A cylinder is defined by the circle that gives the top and bottom faces or alternatively, the cross section, & it's axis. A cylinder running parallel to the z-axis has an axis that is parallel to the z-axis. The equation of such a cylinder is given by the equation of the circle of cross-section with the assumption that a point in 3 dimension lying on the cylinder has 'x' & 'y' values satisfying the equation of the circle & that 'z' can be any value.

That is, in cartesian coordinates, the equation of a cylinder running parallel to the z-axis having radius 'p' with center at (a, b) is given by,

(x-a)^{2}+(y-b)^{2}=p^{2}

Here, it is given that the center is at origin & radius is 1. That is, here, we have, a=b=0,p=1. Then the equation of the cylinder in cartesian coordinates is,

x^{2}+y^{2}=1

Now, the spherical coordinate system is represented by (\rho,\theta,\phi)

The relation between cartesian and spherical coordinates is given by,

x=\rho sin\phi cos\theta,y=\rho sin\phi sin\theta, z= \rho cos\phi

Thus, the equation of the cylinder can be rewritten in spherical coordinates as,

(\rho sin\phi cos\theta)^{2}+(\rho sin\phi sin\theta)^{2}=1

\Rightarrow \rho^{2} sin^{2}\phi cos^{2}\theta+\rho^{2} sin^{2}\phi sin^{2}\theta=1

\Rightarrow \rho^{2} sin^{2}\phi (cos^{2}\theta+sin^{2}\theta)=1

\Rightarrow \rho^{2} sin^{2}\phi=1 (As sin^{2}\theta+cos^{2}\theta=1)

Note that \rho represents the distance of a point from the origin, which is always positive. \phi represents the angle made by the line segment joining the point with z-axis. The range of \phi is given as 0\leq \phi\leq \pi. We know that in this range the sine function is positive. Thus, we can say that sin\phi is always positive.

Thus, we can square root both sides and only consider the positive root as,

\Rightarrow \rho sin\phi=1

This is the required equation of the cylinder in spherical coordinates.

Final answer:

(a) The equation of the given sphere in cylindrical coordinates is r^{2}+z^{2}=25

(b) The equation of the given cylinder in spherical coordinates is \rho sin\phi=1

7 0
3 years ago
Heeeeeelllppp me please!!
IrinaK [193]

Answer:

A. 4:5 for each individual tile

B. 800

C.800:1800

D. I cannot answer this question because the number is half erased and i am not good in that area.

Hope this helps anyway!


Step-by-step explanation:


8 0
3 years ago
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