Answer:
10
Step-by-step explanation:
Rate of drainage for pump A and B = [1 pool drained]/[6 hours]
Rate of drainage for pump A (older pump) = [1 pool drained]/[15 hours]
Rate for pump B (newer pump) = [1 pool drained]/[t hours]
Thus, adding the rate of drainage of A and B,
1/t + 1/15 = 1/6
t=10
Answer:
The maximum amount of money the chemistry club can spend without going over their buget is $81.4 ... With a total of 6 hours their allowed to use the room for.
Step-by-step explanation:
$49 is our constant and will not change. 5.40 however will. Let's use variable h for the amount hours they can rent the room for. Now we can make an inequality;
49+ 5.40h < 86.80
5.40h < 86.80
5.4h< 37.8
h< 7
Now that we know h will have to be less than seven for the chemistry club to spend less than their buget we can find that 6 is the maxium amount of hours they can spend in the room while staying within their budget.
(This answer does not consider decimals or half hours)
Answer:
Step-by-step explanation:
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