Try this solution:
dx/siny=dy/cos2x;
sinydy=cos2xdx;
cosy=-1/2 sin2x+C.
Answer:
B- Parallelogram PQRS is also a rhombus.
Step-by-step explanation:
Given
Parallelogram PQRS with perpendicular diagonals
Required
Which of the option is true
(a) PQRS can be a rectangle
A rectangle do not have perpendicular diagonals.
Hence, (a) is false
<em>If (a) is false, then (d) is also false</em>
(b) PQRS can a rhombus
The diagonals of a rhombus are not perpendicular.
So (b) <em>is true</em>
<em>No need to check for (c), since only option is true</em>
Subtract 15 from both sides that gets rid of 15 and your left with 3b =30b divide 3 on both sides and the answer is 10
<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>
And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>
Answer:
I say 12, but i can be wrong.
Step-by-step explanation:
