Given that
the weight of football players is distributed with a mean of 200 pounds and a standard deviation of 25 pounds.
And we need to find What is the minimum weight of the middle 95% of the players?
Explanation -
Using the Empirical Rule, 95% of the distribution will fall within 2 times of the standard deviation from the mean.
Two standard deviations = 2 x 25 pounds = 50 pounds
So the minimum weight = 200 pounds - 50 pounds = 150 pounds
Hence the final answer is 150 pounds.
(y-4) (y-3)
you look at 12 and see what two factors of 12 add up to -7 and -4 times -3 is 12 and -4+-3 = -7
Answer: that's false
Step-by-step explanation:
degrees of freedom=(r-1)(c-1)
If I'm wrong I'm sorry
Answer:
50%
Step-by-step explanation:
Step 1 : Firstly, you divide 100% by 2
Step 2 : This will end up giving you an answer of 50%
Step 3 : Your answer is 50%
