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allochka39001 [22]
3 years ago
10

Of the words, which is five-sixths of the list. How many words are on the list?

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
3 0
I THINK it is 23 i hope it helps
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True or False? Tell whether the pair of ratios form a proportion. 8/12 and 14/21 Please explain why you chose what you chose​
erik [133]

Answer:

True; The pair of ratios form a proportion.

Step-by-step explanation:

To tell whether these two ratios are proportional, we can simplify each of them

\frac{8}{12} =\frac{2}{3}

\frac{14}{21} =\frac{2}{3}

As both ratios simplify into the same ratio, they are proportional.

8 0
3 years ago
How old are you?non statiscal
dem82 [27]

Answer:

5

Step-by-step explanation:

the steps are simple my mom made me which then I had to wait 5 weeks

3 0
3 years ago
Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as
stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

c^{2}=a^{2}+b^{2}

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

a=7\ cm\\c=13\ cm

substitute

13^{2}=7^{2}+b^{2}

Solve for b

169=49+b^{2}

b^{2}=169-49

b^{2}=120

b=\sqrt{120}\ cm

b=10.95\ cm

we have that

<em>Jayden's Work</em>

a^{2}+b^{2}=c^{2}

a=7\ cm\\b=13\ cm

substitute and solve for c

7^{2}+13^{2}=c^{2}

49+169=c^{2}

218=c^{2}

c=\sqrt{218}\ cm

c=14.76\ cm

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

<em>Sheridan's Work</em>

a^{2}+b^{2}=c^{2}

a=7\ cm\\c=13\ cm

substitute

7^{2}+b^{2}=13^{2}

Solve for b

49+b^{2}=169

b^{2}=169-49

b^{2}=120

b=\sqrt{120}\ cm

b=10.95\ cm

therefore

Sheridan's Work is correct

6 0
3 years ago
Read 2 more answers
Please help immediately very confused
AlexFokin [52]

Answer:

4.5

Step-by-step explanation:

162/360=0.45

0.45*10=4.5

3 0
3 years ago
Read 2 more answers
Que es un término algebraico
Tems11 [23]

Answer: an algebraic term?

Step-by-step explanation:

8 0
3 years ago
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