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snow_tiger [21]
3 years ago
6

The local high school is hosting an ice cream social for new students. They record the ice cream choices of the students through

out the event. What is the probability that a male student chooses chocolate ice cream? A. 6/23 B. 4/7 C. 3/7 D. 3/22

Mathematics
2 answers:
UkoKoshka [18]3 years ago
7 0
3/7 is the correct answer

melomori [17]3 years ago
5 0

Answer:

Option C is correct

\frac{3}{7}

Step-by-step explanation:

By definition of probability:

\text{Probability} = \frac{\text{Number of possible outcomes}}{\text{Total number of outcomes}}

As per the given statement:

The local high school is hosting an ice cream social for new students.

They record the ice cream choices of the students throughout the event.

We have to find the probability that a male student chooses vanilla ice cream.

Total number of vanilla ice cream = 14

Number of  male student chooses vanilla ice cream = 6

then;

By definition we have;

\text{Probability that a male student chooses vanilla ice cream} = \frac{6}{14} = \frac{3}{7}

Therefore, \frac{3}{7} is the probability that a male student chooses vanilla ice cream

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Jumbo eggs in Australia, on average, are supposed to weigh 68g. Margot is in charge of a quality control test that involves weig
Andrej [43]

Answer:

0.9987 = 99.87% probability that the mean weight of 4 eggs in a package is less than 68.5g

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean weight of 67g and a sample standard deviation of 1g.

This means that \mu = 67, \sigma = 1

Sample of 4

This means that n = 4, s = \frac{1}{\sqrt{4}} = 0.5

What is the probability that the mean weight of 4 eggs in a package is less than 68.5g?

This is the pvalue of Z when X = 68.5. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{68.5 - 67}{0.5}

Z = 3

Z = 3 has a pvalue of 0.9987

0.9987 = 99.87% probability that the mean weight of 4 eggs in a package is less than 68.5g

6 0
3 years ago
Read 2 more answers
I need how with plz
omeli [17]

Answer:

165 degrees

Step-by-step explanation:

According to the protractor, the angle stretches from 10 degrees to 175 degrees. Subtract 10 from 175 to get the total measurement, and you will get 165. The angle is 165 degrees.

6 0
3 years ago
Read 2 more answers
. upper left chamber is enlarged, the risk of heart problems is increased. The paper "Left Atrial Size Increases with Body Mass
Sonbull [250]

Answer:

Part 1

(a) 0.28434

(b) 0.43441

(c) 29.9 mm

Part 2

(a) 0.97722

Step-by-step explanation:

There are two questions here. We'll break them into two.

Part 1.

This is a normal distribution problem healthy children having the size of their left atrial diameters normally distributed with

Mean = μ = 26.4 mm

Standard deviation = σ = 4.2 mm

a) proportion of healthy children have left atrial diameters less than 24 mm

P(x < 24)

We first normalize/standardize 24 mm

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (24 - 26.4)/4.2 = -0.57

The required probability

P(x < 24) = P(z < -0.57)

We'll use data from the normal probability table for these probabilities

P(x < 24) = P(z < -0.57) = 0.28434

b) proportion of healthy children have left atrial diameters between 25 and 30 mm

P(25 < x < 30)

We first normalize/standardize 25 mm and 30 mm

For 25 mm

z = (x - μ)/σ = (25 - 26.4)/4.2 = -0.33

For 30 mm

z = (x - μ)/σ = (30 - 26.4)/4.2 = 0.86

The required probability

P(25 < x < 30) = P(-0.33 < z < 0.86)

We'll use data from the normal probability table for these probabilities

P(25 < x < 30) = P(-0.33 < z < 0.86)

= P(z < 0.86) - P(z < -0.33)

= 0.80511 - 0.37070 = 0.43441

c) For healthy children, what is the value for which only about 20% have a larger left atrial diameter.

Let the value be x' and its z-score be z'

P(x > x') = P(z > z') = 20% = 0.20

P(z > z') = 1 - P(z ≤ z') = 0.20

P(z ≤ z') = 0.80

Using normal distribution tables

z' = 0.842

z' = (x' - μ)/σ

0.842 = (x' - 26.4)/4.2

x' = 29.9364 = 29.9 mm

Part 2

Population mean = μ = 65 mm

Population Standard deviation = σ = 5 mm

The central limit theory explains that the sampling distribution extracted from this distribution will approximate a normal distribution with

Sample mean = Population mean

¯x = μₓ = μ = 65 mm

Standard deviation of the distribution of sample means = σₓ = (σ/√n)

where n = Sample size = 100

σₓ = (5/√100) = 0.5 mm

So, probability that the sample mean distance ¯x for these 100 will be between 64 and 67 mm = P(64 < x < 67)

We first normalize/standardize 64 mm and 67 mm

For 64 mm

z = (x - μ)/σ = (64 - 65)/0.5 = -2.00

For 67 mm

z = (x - μ)/σ = (67 - 65)/0.5 = 4.00

The required probability

P(64 < x < 67) = P(-2.00 < z < 4.00)

We'll use data from the normal probability table for these probabilities

P(64 < x < 67) = P(-2.00 < z < 4.00)

= P(z < 4.00) - P(z < -2.00)

= 0.99997 - 0.02275 = 0.97722

Hope this Helps!!!

7 0
3 years ago
Please help<br><br><br> AOB = ?<br><br> BOC = ?<br><br> BOD = ?
goldfiish [28.3K]
From the diagram, we know that it is an angle that adds up to 360

So

x+4x+2x+10+5x+50=360


Gather like terms

12x+60=360

Move sixty to the other side as a negative number

12x=300

Divide both sirs by twelve

x is equal to 25

AOB is 2x+10

Sub x in 2*25+10

AOB is 60

BOC is 5x+50

5*25+50, which is 175

BOD is x+2x+10

Which is 3x+10

Sub x

3*25+10 which is 85

:)
7 0
3 years ago
Read 2 more answers
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alexandr1967 [171]

Answer:

Im so sorry!

Step-by-step explanation:

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8 0
3 years ago
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