Answer:
60 minutes
Step-by-step explanation:
Let the number of minutes be represented as x
For Plan A
Plan A charges $35 plus $0.25 per minute for calls.
$35 + $0.25 × x
35 + 0.25x
For Plan B
Plan B charges $20 plus $0.50 per minute for calls.
$20 + $0.50 × x
20 + 0.50x
For what number of minutes do both plans cost the same amount?
This is calculated by equating Plan A to Plan B
Plan A = Plan B
35 + 0.25x = 20 + 0.50x
Collect like terms
35 - 20 = 0.50x - 0.25x
15 = 0.25x
x = 15/0.25
x = 60 minutes.
Hence, the number of minutes that both plans cost the same amount is 60 minutes
Answer:

Step-by-step explanation:
we have
<em>The equation of the first line</em>
------> equation A
<em>The equation of the second line</em>
------> equation B
Solve the system of equations by elimination
Multiply equation A by -4 both sides
--------> equation C
Adds equation B and equation C

<em>Find the value of x</em>
substitute the value of y


Multiply by 3 both sides


therefore
The solution to the system of equations is the point 
Do 3 divided by 53 to find the cost of one ticket and then multiply the that number with 7
Answer:
11 of 20p, 22 of 10p and 33 of 5p
Step-by-step explanation:
Eva has 20p, 10p and 5p coins, total of £6.05 = 605p
Let 20p=x, 10p=y, 5p=z
<u>Then</u>:
- 20x + 10y + 5z = 605
- y : x = 2 : 1 ⇒ x= y/2
- y : z = 2 : 3 ⇒ z= 3y/2
<u>Rewriting the first equation considering next two:</u>
- 10y + 10y + 7.5y = 605
- 27.5y = 605
- y= 605/27.5
- y= 22
- x= y/2 = 22/2 = 11
- z = 3y/2 = 3*11 = 33
<u>Answer:</u> 11 of 20p coins, 22 of 10p coins and 33 of 5p coins