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Dmitrij [34]
3 years ago
7

Given f(x)=} (7 – x)2 , what is the value of f(21) ?

Mathematics
2 answers:
natita [175]3 years ago
8 0

Answer:

-196

Step-by-step explanation:

f(x) = (7-x)^2

     plug in the value of x

f(x) = (7-21)^2

      subtract 7 from 21

f(x) = (-14)^2

      now take -14 to the 2nd power

f(x) = -196

      your answer would be -196

Dafna11 [192]3 years ago
6 0

Answer:-28

Here x would be 21 so you fill in 21 for x.

f(21)=(7-21)2

Then you would subtract 21 from 7, leaving you with -14. You do this because you have to follow BEDMAS (brackets, exponents, division, multiplication, addition, subtraction).

f(21)=(-14)2

Lastly, you multiply the -14 by 2 because you have to get it out of the brackets. So you would be left with f(21)=-28

f(21)=-28

Step-by-step explanation:

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