Answer:
The equation for rational function for given asymptotes is
f(x)=(-4x^2-6)/{(x-3)(x+3)}
Step-by-step explanation:
Given:
vertical Asymptotes at x=3 and x=-3 and a horizontal asymptote at
y=-4 i.e parallel to x axis.
To find:
equation of a rational function i.e function in form p/q
Solution;
the equation should be in form of p/q
Numerator :denominator.
Consider f(x)=g(x)/h(x)
as vertical asymptote are x=-3 and x=3
denominator becomes, (x-3) and (x+3)
for horizontal asymptote to exist there should have same degrees in numerator and denominator which of '2'
when g(x) will be degree '2' with -4 as coefficient and dont have any real.
zero.
By horizontal asymptote will be (-4x^2 -6)
The rational function is given by
f(x)=g(x)/h(x)
={(-4x^2-6)/(x-3)(x+3)}.
The first step is to subtract 6 from both sides to cancel it out. You will be left with -3x= -1.
Yes, the variable of interest is two-dimensional.
If you are making a graph about the area of a country, that is a two dimensional measurement. It would be ok to make a graph that is also 2 dimensional.
The fraction will continue to be the same numerator "1". However the denominator will be a greater number. Such as 4. Then you will know it is broken into more peices (as being a greater number). These pieces will automatically be a smaller fraction.
So, in order to know if a fraction is less then 1/2, it will have a greater denominator.
hope this helps :)