About 20mins
2/3 of an hour is 40min
2/3 of 0.5(30min) = 20(I'm not too sure)
A total of 35+21 = 56 tickets were sold. The probability of 5 men winning is the ratio
C(21, 5)/C(56, 5) = 20,349/3,819,816 ≈ 0.00533
_____
C(n, k) is the number of ways k items can be chosen from n items. Its value is
= n!/(k!*(n-k)!)
See the attached figure to better understand the problem
we know that
<span>The inscribed angle in a circle measures half of the arc it comprises.
</span>in this problem
the inscribed angle= ∠ACB
and the arc it comprises measures 180°
then
the ∠ACB=180°/2-------> ∠ACB=90°
<span>applying the Pythagorean theorem
</span>AC²+CB²=AB²-------> AB²=24²+7²-------> AB²=625------> AB=25 cm
the diameter of circle is AB
radius=25/2--------> r=12.5 cm
[the area of a half circle]=pi*r²/2------> pi*12.5²/2--------> 245.44 cm²
[area of triangle ABC]=AC*CB/2--------> 24*7/2-------> 84 cm²
[the area of the shaded region]=[the area of a half circle]-[area of triangle ABC]
[the area of the shaded region]=245.44-84-------> 161.44 cm²
the answer is
the area of the shaded region is 161.44 cm²
The answer is , because i searched it up