Sumalee and danielle are selling

It takes 30 minutes or less to walk from home to school and back home again when walking at 30m/min to school and walking at 45

erik [133]

Answer:

540m

Step-by-step explanation:

From the question,we are told

It takes 30 minutes or less to walk from home to school and back home again

Time walking to school = 30 or less minutes

Time walking from school = 30 less minutes

Speed walking to school = 30m/min

Speed walking from school = 45m/min

The question asked us to find the Distance between home and school

The formula for Distance covered = Speed × Time

Total distance = Total Speed(m/min) × Total time(minutes)

Let the distance between home and school be represented by x

Time to walk from the house to school = x/ 45m/min + x/ 30m/min

= 30 × x + 45 × x/1350

=( 75x / 1350)

Time to walk from school or to school = 30 minutes of less

= 75x/1350 = 30

75x = 1350 × 30

x = 1350 × 30/75

x = 540m

Therefore, distance between home and school = 540m

4 0

3 years ago

Help please with this question

bogdanovich [222]

Answer:

b. x - 2y = 4

Step-by-step explanation:

The two points on the graph are (0, -2) and (4, 0).

Find slope:

m = (y₂ - y₁) / (x₂ - x₁)

= (0 - (-2)) / (4 - 0)

= 2 / 4

= 1 / 2

Find y intercept using anyone of the points above:

y = mx + b

-2 = 1/2(0) + b

b = -2

Use m and b to make equation of line:

y = mx + b

y = 1/2x - 2

Possible answers:

a. 4x - 2y = 4

-2y = -4x + 4

y = 2x - 2

b. x - 2y = 4

-2y = -x + 4

y = 1/2x - 2

c. -2x + 4y = -4

4y = + 2x - 4

y = 1/2x - 1

Only choice b equals the equation of line above.

4 0

3 years ago

One positive integer is 7 less than twice another. The sum of their squares is 346. Find the integers. should be 2 answers

vovikov84 [41]

Answer:

the two positive integers are x= 15, and y = 11

Step-by-step explanation:

Let the first integer be x

Let the second integer be y

from the problem we can decode the following equations

$x=2y-7$ ---------------------------- equation 1

$x^{2} + y^{2}= 346$ -------------------------equation 2

substituting the value of x into equation 2, we have

$(2y-7)^{2} + y^{2}= 346 --------------equation 3$

expanding, we have

$4y^{2}-28y+49+y^{2}=346$

$5y^{2}-28y-297 = 0$

from this, y = 11 or y = -5.4

since our answer is a positive integer, we will have to pick the first value of y which is y = 11

substituting the value of y into equation 1, we have

$x= 2(11)-7=15$

hence x = 15

Therefore, we have x= 15, and y = 11

these are the two positive integers

7 0

3 years ago

HELP!(WILL GIVE BRAINLIEST) I ALSO HAVE LOTS OF POINTS IN MY PROFILE.

irga5000 [103]

Answer:

$10.55

Step-by-step explanation:

8 0

3 years ago

One angle of a triangle measures 140°. The other two angles are in a ratio of 7:13. What are the measures of those two angles?

nexus9112 [7]

The unknown angles are in a ratio of 7 to 13.

Let 7x represent the smaller measure.Then, 13x represents the larger measure.
7x + 13x + 140 = 180
20x + 140 = 180
20x = 40
x = 2

7x = 7 * 2 = 14

13x = 13 * 2 = 26

The measures are 14 degree and 26 degrees.

4 0

3 years ago