Answer: the system has no solution.
Step-by-step explanation:
\displaystyle\\
\left \{ {{x^2y=16\ \ \ \ \ (1)} \atop {x^2+4y+16=0\ \ \ \ \ (2)}} \right. .\\
Multiply\ both\ sides\ of\ the\ equation\ (2)\ by\ y\ (y\neq 0):\\
x^2y+4y^2+16y=0\\
We\ substitute\ equation\ (1)\ into\ equation\ (2):\\
16+4y^2+16y=0\\
4y^2+16y+16=0\\
4*(y^2+4y+4)=0\\
4*(y^2+2*y*2+2^2)=0\\
4*(y+2)^2=0\\
Divide\ both\ sides\ of\ the \ equation\ by\ 4:\\
(y+2)^2=0\\
(y+2)*(y+2)=0\\
So,\ y+2=0\\
y=-2.\\

Answer:
24.351
Step-by-step explanation:
Look at the two faces which are parallel. Those are the bases and give the prism its name. In this case, the triangles are the parallel faces. Therefore, they are the bases and the prism is a triangular prism
Multiply all of there destination and you'll get your answer
Answer:
He is incorrect
If there was 2 sides of 6 inches, the base can be 5 inches and it could be an isoscles triangle
Step-by-step explanation: