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4 years ago

The highest common factor of had of 12, 15 and 60

Mathematics

1 answer:

Natalija [7]4 years ago

4 0

Answer:

the highest common factor of 12 , 15 and 60 is 3

Step-by-step explanation:

12 = 1, 2, 3, 4, 6, 12
15= 1, 3, 5, 15
60=1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

So thus 3 is the HCF that is why i underlined it

Hope this helps

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Translate each of the following English statements into logical expressions. The domain of discourse is the set of all real numb

Scilla [17]

Answer:

A) З x,y : ( x/y < 1, y/x < 1 )

B) ∀ Y : ( Y > 0 = 1/Y > 0 )

C) з x,y : ( x+y = xy )

D) ∀ x,y : [ ( x>0 ) ∧( y > 0 ) = (( x/y > 0 ) ∧ ( y/x > 0 ))

E ) ∀ y : [ ( y > 0 ) ∧ ( y < 1) = ( 1 / y > 1 )

F) n ( ( з x ∀ y ( x <y ) )

G) ∀x (( x ≠ 0 ) = ( зy ( xy = 1 ) ))

H) ∀x ( (x≠0) = ( з! y (xy = 1))

Step-by-step explanation:

since the domain of discourse is a set of all real numbers the logical expressions of the English statements are expressed with respect to real number:

A) З x,y : ( x/y < 1, y/x < 1 )

B) ∀ Y : ( Y > 0 = 1/Y > 0 )

C) з x,y : ( x+y = xy )

D) ∀ x,y : [ ( x>0 ) ∧( y > 0 ) = (( x/y > 0 ) ∧ ( y/x > 0 ))

E ) ∀ y : [ ( y > 0 ) ∧ ( y < 1) = ( 1 / y > 1 )

F) n ( ( з x ∀ y ( x <y ) )

G) ∀x (( x ≠ 0 ) = ( зy ( xy = 1 ) ))

H) ∀x ( (x≠0) = ( з! y (xy = 1))

4 0

3 years ago

Find the value of each variable

sesenic [268]

Answer:

x=16

y= 100

Step-by-step explanation:

<1 and <3 are vertical angles so they are equal

5x = 80

Divide each side by 5

5x/5 = 80/5

x = 16

Angles 2 and 3 are supplementary since they form a straight line, they will add to 180

<2 + <3= 180

y+80 = 180

Subtract 80 from each side

y+80-80 = 180-80

y= 100

5 0

3 years ago

A radioactive material decays over time. Find k, if

Arturiano [62]

Answer is in the photo. I can only upload it to a file hosting service. link below!

tinyurl.com/wpazsebu

4 0

3 years ago

What is the expression in radical form? (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

8 0

4 years ago

I really need help on this

konstantin123 [22]

Graph B has y-intercept at 2

5 0

3 years ago

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