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amm1812
3 years ago
15

Please find the domain

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
8 0
So there are two things: 
Domain and Range
Domain is the x value
and Range is the y value
THE Y VALUE IS ALWAYS DEPENDENT ON THE X VALUE
Therefore, the range is always dependent on the domain
In this line, there are arrows at the end of the line meaning that it goes on and on
If you look at it closer, the x value goes on and on without limitations
But the y value changes based on where the x value is, so it can't go anywhere it wants like the x value can

Therefore, if the x value or DOMAIN is infinite, that's the same as saying the *Domain is limited to all real numbers* since all other options restrict the x value AND because the term "all real numbers" basically means "infinite" in graphing

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rjkz [21]
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8 0
3 years ago
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Find the distance between the points given. (-3, 2) and (9, -3) A √37 B √61 C 13​
Kitty [74]

Answer:

\huge{ \fbox{ \sf{13 \: units}}}

Option C is correct.

Step-by-step explanation:

\star{ \sf{ \: Let \: the \: points \: be \: a \: and \: b}}

\star{ \sf{ \: let \: A(-3, 2) \: be \: (x1 \:, y1) \:  and  \: B(9, -3) \: be \: (x2 \:, y2) }}

\underline{ \sf{Finding \: the \: distance \: between \: the \: given \: points}} :

\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

\mapsto{ \sf{  \sqrt{ {(9 - ( - 3))}^{2} +  {( - 3 - 2)}^{2}  } }}

\mapsto{ \sf{ \sqrt{ {(9 + 3)}^{2}  +  {( - 3 - 2)}^{2} }}}

\mapsto{ \sf{ \sqrt{ {(12)}^{2}  +  {( - 5)}^{2} } }}

\mapsto{ \sf{ \sqrt{144 + 25}}}

\mapsto{ \sf{ \sqrt{169} }}

\mapsto{ \sf{ \sqrt{ {(13)}^{2} } }}

\mapsto{ \sf{ 13 \: units}}

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

7 0
3 years ago
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N76 [4]
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3 years ago
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Step-by-step explanation:

4 0
3 years ago
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Combine like terms

7a+b-9c+17d

8 0
3 years ago
Read 2 more answers
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