Question

What is the equation of a parabola whose vertex is (0, 5) and whose directrix is x = 2? y2 = 8(x − 5) 8(y − 5) = x2 (y − 5)2 = 8x (y − 5)2 = -8x

Answer 1

The answer is going to be A
hope this helps

Answer 2

Answer:

$(y-5)^2=-8x$

Step-by-step explanation:

vertex is (0, 5) and whose directrix is x = 2

Vertex (0,5), x=0 and y=5

The distance between x=0 and x=2 is 2 units

The distance between vertex and directrix is P

p= 2

General equation of horizontal parabola is

$(y-k)^2=-4p(x-h)$

h=0, y= 5, p=2

$(y-5)^2=-4(2)(x-0)$

$(y-5)^2=-8x$