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jok3333 [9.3K]
3 years ago
6

a number rounded to the nearest hundred thousand is 400,000.the same number rounded to the nearest ten thousand 350,000.what cou

ld be the number
Mathematics
1 answer:
Radda [10]3 years ago
7 0

Answer:

354,900

Maybe.

It would work, I believe.. Hope this helps!

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The answer and how to solve it
blondinia [14]
U would simpiphy it to then get the awnser
3 0
3 years ago
You want to buy birthday hats, cards, and teddy bears for your best friends birthday party. You buy the products for wholesale p
Naya [18.7K]

Answer:

I will create a five by four matrix to indicate the costs of the products.  The matrix will have five vertical columns and four horizontal rolls.  The vertical columns will show the product categories and the total costs for all the products and decorations.  The horizontal rolls will show the product costs, the decoration costs, and the total costs for each product category.

The size and shape of the matrix will be 5 by 4 with squared boxes.

Step-by-step explanation:

Products/Costs         Hats         Cards      Teddy    Total Costs

Product costs           $2.50       $0.90       $3.10        $6.50

Decoration costs      $1.50       $0.60        $1.70        $3.80

Total costs               $4.00        $1.50       $4.80       $10.30

6 0
3 years ago
Find 25% of 80 kg A 40kg B 10kg C 8kg D 20kg help me plss​
vova2212 [387]

Answer:

25% of 80 is D. 20kg

Step-by-step explanation:

50% of 80 is 40 and we know that 25% is half of 50%, so half of 40 would be 20.

So, the answer is D. 20kg

Hope this helps! :)

8 0
2 years ago
Need help with this confusing
Dahasolnce [82]

Answer:

The blanks are 18 and 20

equivalent ratios

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
What is the length of the conjugate axis?<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%28x-2%29%5E2%7D%7B36%7D%20-%20%5Cfrac
LuckyWell [14K]

Answer:

the length of the conjugate axis  is 16

Step-by-step explanation:

We know that the general equation of a hyperbola with transverse horizontal axis has the form:

\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1

Where the point (h, k) are the coordinates of the center of the ellipse

2a is the length of the transverse horizontal axis

2b is the length of the conjugate axis

In this case the equation of the ellipse is:

\frac{(x-2)^2}{36} + \frac{(y+1)^2}{64} = 1

Then

b^2 = 64\\\\b = \sqrt{64}\\\\b = 8\\\\2b = 16

Finally the length of the conjugate axis is 16

5 0
3 years ago
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