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SOVA2 [1]
2 years ago
13

If each pound of beef cost $2.59 how much does 3 1/4 pounds cost ?

Mathematics
1 answer:
faltersainse [42]2 years ago
5 0

Answer:

$8.35

Step-by-step explanation:

2.59*3 = 7.70

2.59/4 = .65

7.70+.65= $8.35

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Justin used 3/4 of a gallon of paint on 3/4 of a wall. How many gallons does he need for one wall?
blondinia [14]

Answer:

Step-by-step explanation:

1/4

7 0
3 years ago
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Joel has a goal to practice is clarinet for 4 1/2 hours per week the list below shows the number of hours Chihuahuas practice so
Natasha_Volkova [10]

Complete question:

Joel has a goal to practice his clarinet for 4 1/2 per week. The list below shows the number of hours Joel has a practiced so far for the week. Monday 1 1/2 hours Wednesday 1 1/4 hours Thursday 1 hour How many more hours does he need to practice this week to meet his goal

Answer: 3/4 hours

Step-by-step explanation:

Target hours = 4 1/2 hours = 9/2 hours

Number of hours so far :

(1 1/2 + 1 1/4 + 1) = (3/2 + 5/4 + 1) hours

Total so far :

L. C. M of denominator = 4

(6 + 5 + 4) /4 = 15/4

Number of hours left to meet his target equals :

Target hours - total so far

( 9/2 - 15/4)

L. C. M of denominator = 4

(18 - 15) / 4 = 3/4 hours

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7 0
3 years ago
Someone please help asap
joja [24]
Solve the equation of the function for n.

a(n) = 3n - 20

a = 3n - 20

a + 20 = 3n

(a + 20)/3 = n

n = (a + 20)/3

n(a) = (a + 20)/3
6 0
2 years ago
An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

Approximately 0.15 (360 / 2401.) (Assume that the choices of the 5 passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 7 floors.)

Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

5 0
2 years ago
I’ll mark brainliest
Naddik [55]

Answer:

A

Step-by-step explanation:

ok so pretend the 2.00 was just 2 so whats 8 divided by 2? 4 right so if we test that witht he other problems its the same so its A

Hope this helps!!!!     :D

4 0
2 years ago
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