Your answer is -4<span>√6. Hope this helps :)</span>
These tables have infinitely many values, but the simplest ones would be:
a) x|y
3|5
6|10
9|15
b) x|y
2|1
4|2
6|3
Your graph for c would look like the attached picture
Answer:
y = 0.25x+1
Step-by-step explanation:
Y= mx+b
m= 0.25
b= 1
hope this helps
Answer: X'(-3, -2), Y'(-5, 1), and Z'(2, -3)
Step-by-step explanation:
Upon reflection across the x-axis, the x-coordinates remain the same while the signs of the y-coordinates flip. So, the coordinates will be X(3, -2), Y(5, 1), and Z(-2, -3).
Upon reflection across the y-axis, the signs of the x-coordinates will flip while the signs of the y-coordinates remain the same. So, the coordinates will be X′(-3, -2), Y′(-5, 1), and Z′(2, -3).
Check the picture below.
something worth noticing 
so, we're really graphing x+2, with a hole at x = 3, however, when x = 3, we know that f(x) = 5, but but but, when x = 3, x+2 = 5, so we end up with a continuous line all the way, x ∈ ℝ, because the "hole" from the first subfunction, gets closed off by the second subfunction in the piece-wise.