All categories

3 years ago

Given -1/2x>6 choose the solution set

Mathematics

1 answer:

kondaur [170]3 years ago

6 0

-1/2x > 6

All you have to do is divide 6 by -1/2, which is -3. The answer is x < -3, the sign got flipped because you divide by a negative number.

You might be interested in

Can someone help with this.

olya-2409 [2.1K]

Answer:

A. S+A

B. (4×3)+(6×2)=$24

8 0

3 years ago

Where is Anita after a bike ride? Plz help me with this question!

Harman [31]

Anita first rode her bike 5 blocks to the east.
She then rode twice as many blocks west. 5*2=10. She rode 10 block west. Subtract 10 from 5: 5-10=-5
She finally rode 8 blocks back east. Add 8 to -5: -5+8=3.
Anita is three blocks east from home.

5 0

3 years ago

PLEASE HELP ASAP *TIMED TEST*

shusha [124]

The answer is C because in y=mx+b form, the “m” stands for the slope.

3 0

3 years ago

What is the place value of 1 in 5,678.321

alukav5142 [94]

<span>The place value of 1 in 5,678.321 is one-one thousands. The one digit is the third place behind the decimal point. The first place behind the decimal point is three one-tenths. The second place behind the decimal is two one-hundredths. A decimal number is a division of one. In other words, it will take a thousand one-one thousands to equal one.</span>

6 0

4 years ago

PLEASE HELP ASAP! I don’t recall how to do this!

MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

$(1.05)^x=1.885$

In order to solve for x, we have to get it out from its position of an exponent. Do that by taking the natural log of both sides:

$ln(1.05)^x=ln(1.885)$

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

$x=\frac{ln(1.885)}{ln(1.05)}$

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

$ln(x*x^2)=5$

Simplifying gives you

$ln(x^3)=5$

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

$ln(x)=\frac{5}{3}$

Take the inverse ln by raising each side to e:

$e^{ln(x)}=e^{\frac{5}{3}}$

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

$\frac{1}{2}=e^{.1x}$

"Undo" that e by taking the ln of both sides:

$ln(.5)=ln(e^{.1x})$

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others. Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

$(2^2)^x-6(2)^x=-8$

Now we will bring over the -8 by adding:

$(2^2)^x-6(2)^x+8=0$

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution. Let's let $u=2^x$

When we do that, we can rewrite the polynomial as

$u^2-6u+8=0$

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor. Now we have to put it back in:

$2^x=4,2^x=2$

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

$2^2=2^x$

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

$2^x=2^1$

Now that the bases are the same, we can say that

x = 1

5 0

3 years ago