3 years ago

Optimization Calculus Problem!

1 answer:

vladimir1956 [14]3 years ago

8 0

2s -5488/s^2 = (2s*s^2)/s^2 -5488/s^2 = (2s^3-5488)/s^2
Since this thing is = 0,
0 multiply by its denominator is still 0
So 2s^3 - 5488 =0
s^3= 5488/2= 2744
s= cube root 2744

its alot if mental sum so they dont show step by step

You might be interested in

Need help on this. I would appreciate it a lot!

umka2103 [35]

Answer: The second answer choice

4 0

3 years ago

ABC is a triangle.<br> Work out the size of the angle marked p.

mario62 [17]

Answer:

p= angle180_(50+70)

p=180_120

angle p=60

5 0

2 years ago

(−4)4 is the question. it is in math

Zinaida [17]

-4 * 4 = -16

<h2>This is the answer to math</h2>

4 0

3 years ago

Read 2 more answers

NEED HELP ASAP 15 POINTS

NeX [460]

Use the app Socratic it helps!!

4 0

3 years ago

Consider the following function. f(x) = 9 − x2/3 Find f(−27) and f(27). f(−27) = f(27) = Find all values c in (−27, 27) such tha

oksano4ka [1.4K]

I guess the function is $f(x)=9-x^{2/3}$ . Then $f(-27)=0$ and $f(27)=0$ .

The derivative is $f'(x)=-\dfrac23 x^{-1/3}$ , but there is no $c$ such that

$-\dfrac23c^{-1/3}=0$

This doesn't contradict Rolle's theorem because $f'(0)$ does not exists. In other words, $f$ is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")

6 0

3 years ago